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3 years ago

Bro i don’t even know why y’all gm got me doing this for real

Mathematics

2 answers:

jolli1 [7]3 years ago

5 0

Answer:

Dude, so true-

Step-by-step explanation:

DiKsa [7]3 years ago

5 0

Answer:

???

Step-by-step explanation:

Give me a question and I can help you

You might be interested in

What is the opposite of a number called? I forgot. Like -6 is the ______ of 6.

JulijaS [17]

The opposite of a number is called its inverse.

6 0

3 years ago

Help me with this please!!!!!

garri49 [273]

Answer:

True, the point (-5, 2) is inside of the circle (lying on it) centered at (0, 7)

Step-by-step explanation:

Hope this helps! Leave any questions or concerns in the comments! byeee <3

3 0

4 years ago

Melissa reserves another rectangular patch in her vegetable garden for growing bell peppers. Since the space that she can reserv

Otrada [13]

Answer:

Quadratic, 16, 18, 6

Step-by-step explanation:

Did this assignment myself

7 0

3 years ago

Simplify - tanx-(sec^2 / tanx)

Mashcka [7]

Answer:

-cot(x)

Step-by-step explanation:

tanx-(sec^2x / tanx)

Lets get a common denominator of tan

tan x * tan x/ tan -sec ^2 x/ tan x

tan ^2 x - sec ^2 x

---------------------------

tan x

We know than sec^2 - tan^2 =1 (trig identity) so factor out -1

-1(-tan ^2 x + sec ^2 x)

---------------------------

tan x

-1(1)

---------------------------

tan x

-1

----------

tan (x)

We know 1/ tan x = cot (x)

- cot(x)

7 0

3 years ago

What are the solutions to the quadratic equation 9x(2) + 64 = 0?

Contact [7]

Answer:

Solution of given quadratic equation is

$(\frac{8i}{3}, -\frac{8i}{3} )$

Step-by-step explanation:

The given quadratic equation is

$9x^2 + 64 = 0$

The general form of the quadratic equation is given by

$ax^2 + bx + c = 0$

Comparing the general form with the given quadratic equation

$a = 9\\b = 0\\c = 64$

The solutions of the quadratic equation is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Substitute the values of a, b and c

$x=\frac{-0\pm\sqrt{0^2-4(9)(64)}}{2(9)}$

$x=\frac{\pm\sqrt{-2304}}{18}$

$x=\frac{\pm48i}{18}$

$x=\frac{\pm8i}{3}$

$x=\frac{8i}{3}$

and

$x=-\frac{8i}{3}$

Where i represents iota which means that the given quadratic equation has complex roots.

So the solution of given quadratic equation is

$(\frac{8i}{3}, -\frac{8i}{3} )$

The factored form of the given quadratic equation is

$(x+ \frac{8i}{3}) (x- \frac{8i}{3}) = 0$

6 0

3 years ago