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IgorC [24]
2 years ago
8

What is the 13th term of the geometric sequence 4, 12, 36, 108, ...?

Mathematics
1 answer:
bogdanovich [222]2 years ago
7 0

Answer: 2,125,764

Step-by-step explanation:

You can use the equation y=ar^n-1 to find the 13th term where a is the starting term, r is the common ratio, and n is the nth term

The next number is 12/4=3 times greater than the first. So if this sequence is a geometric one, then the next term must be 12*3=36. This is true, and the next term must be 36*3=108, which is also true. Therefore this sequence is a geometric one and its common ratio is 3. Therefore the equation is:

y=4*3^(n-1)

Substitute 13 for n:

y=4*3^(13-1)

y=4*3^12

y=2125764

Therefore, the 13th term of this geometric sequence is 2,125,764

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blsea [12.9K]
The answer to your problem is 0.125
7 0
3 years ago
I need fast help with step by step<br> <img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5E2_1%20%7B%5Cfrac%7B3x-1%7D%7Bx%2B1%7D
Ganezh [65]

Answer:

1.38 to the nearest hundredth.

Step-by-step explanation:

Dividing:

x + 1 ) 3x - 1 ( 3            

          3x + 3

                -4

so (3x - 1) / (x + 1) =  3  - 4 / x+ 1

Integral  of (3  - 4 / x+1 )  = 3x - 4 ln(x + 1)

Between  limits of 1 and 2 we have:

(3(2) - 4 ln 3) - (3 - 4 ln2)

=  1.6056 - 0.2274

= 1.3782.

5 0
4 years ago
Solve using quadratic equation by factoring.<br><br> x^2-9x=-14
Sonbull [250]

Answer:

2,7

Step-by-step explanation:

See image below:)

5 0
3 years ago
Read 2 more answers
in parallelogram ABCD, AC is diagonal, the measure &lt;ABC is 40°, and the measure of &lt;ACD IS 57°. what is the measure of &lt
Nutka1998 [239]

Answer: \angle CAD = 83^\circ Option D


Step-by-step explanation:

In this question we use properties of parallelogram and angle sum property of a triangle.

In parallelogram ABCD


\angle ABC=40^\circ


As, we know that opposite angles of parallelogram are equal


Therefore,


\angle ABC =\angle ADC =40^\circ


Now, in triangle ADC

We know that sum of all the angles of a triangle is =180^\circ


\angle ACD +\angle ADC +\angle DAC =180^\circ


57^\circ +40^\circ +\angle DAC =180^\circ


97^\circ + \angle DAC = 180^\circ

Subtracting 97 from both sides we get


\angle DAC = 180^\circ - 97^\circ


\angle DAC = 83^\circ


Measure of \angle CAD = 83^\circ


3 0
3 years ago
Solve the inequality and graph the solution set on a number line. Express the solution set in both​ set-builder and interval not
shusha [124]
<span>-8 < x -3 < 1
we have two inequations: 
* -8<x-3 and -8+3<x-3+3 or -5 < x or x>-5
*  x-3<1 or x-3+3<1+3 and we have x<4
For all cases we have -5<x<4
or </span><span>interval notations: x</span>∈(-5;4)
have fun
8 0
3 years ago
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