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IgorC [24]
2 years ago
8

What is the 13th term of the geometric sequence 4, 12, 36, 108, ...?

Mathematics
1 answer:
bogdanovich [222]2 years ago
7 0

Answer: 2,125,764

Step-by-step explanation:

You can use the equation y=ar^n-1 to find the 13th term where a is the starting term, r is the common ratio, and n is the nth term

The next number is 12/4=3 times greater than the first. So if this sequence is a geometric one, then the next term must be 12*3=36. This is true, and the next term must be 36*3=108, which is also true. Therefore this sequence is a geometric one and its common ratio is 3. Therefore the equation is:

y=4*3^(n-1)

Substitute 13 for n:

y=4*3^(13-1)

y=4*3^12

y=2125764

Therefore, the 13th term of this geometric sequence is 2,125,764

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Question 6 of 10
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Answer:

- 2

Step-by-step explanation:

Parallel lines have equal slopes

Then the slope of the red line is equal to the slope of the green line, that is

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3 0
2 years ago
Need some help with this question please.
Ksivusya [100]
Use Pythagorean theorem
a^2 + b^2 = c^2
Plug in the info
b = 53, a = 41
41^2 + 53^2 = c^2
1681 + 2809 = c^2
c^2 = 4490
Squareroot of 4490 = 67.007
Perimeter = adding all sides
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Solution: 161.01 meters
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