All categories

3 years ago

X^4 - 3x^2 + 7x^5 type and degree

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

7 0

Answer:

It is a trinomial with a degree 5

Step-by-step explanation:

You might be interested in

Type a digit that makes this statement true.<br><br> 145,00<br> is divisible by 5.

Volgvan

Answer:

145,000÷5=29000

or 14500÷5=2900

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

What is 77 = 4x + 57

Svetach [21]

Answer:

$x=5$

Step-by-step explanation:

$77=4x+57$

Subtract 57 from both sides:

$4x=20$

Divide both sides by 4:

$x=5$

3 0

4 years ago

PLEASE HELP URGENT WILL MARK BRAINLIEST DO NOT WASTE ANSWERS

earnstyle [38]

Answer:

Step-by-step explanation:

it says it is currently at 60 watts, if its tripled (times 3) that meansits times 3 and 60 times 3 is 180 so its A therefore.

8 0

3 years ago

Read 2 more answers

One rectangular solid with a square base has twice the height of another rectangular solid with a square base with the same side

galben [10]

Answer:

First rectangular solid and second Rectangular solid

1. Bases are in the form of square having same dimensions

2. Height of first rectangular solid=2 ×Height of second rectangular solid

The true statements are

A) The bases are congruent.→The meaning of term congruent is that , the two bases are in the shape of square having same dimensions.

(B) No, The solids are not similar.as ratio of side lengths in not same in each case , because the ratio of heights of two solid is equal to .

(D) Volume of first solid = x *x*2 H=2 x²H

Volume of second solid = x*x*H=x²H

Ratio of volumes =2:1

So, option (D) is true.

(E) Surface area of first solid =2[x*x+x*2 H+2 H*x]

=2[x²+4 H*x]=2 *x*[x+4* H]

Surface area of second solid = 2[x*x+x* H+ H*x]=2[x²+2 H*x]=2* x*[x+ 2*H]

Option A, D, E are correct about two solids.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Thank you for any help!

Inessa05 [86]

Answer: Option B.

Step-by-step explanation:

Given the system of inequalities:

$y$

$y>x^2-4$

The solution of the system of inequalities is the region between the parabolas. This region is: below the parabola $y=x^2+6$ and above the parabola $y=x^2-4$

Then, if a point is a solution of the system, then it must be in the region between this parabolas.

You can observe in the figure attached that the point that is in this region is the point (2,6), therefore, the answer is the option B.

7 0

3 years ago