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2 years ago

It takes a car 2.5 h to go from mile marker 15 to mile marker 130. What is the average speed of the car?

Mathematics

2 answers:

adoni [48]2 years ago

8 0

Answer:

42 MPH

Step-by-step explanation:

Please give me brainliest :)

AysviL [449]2 years ago

6 0

50 MPH I think tell me if im wrong.

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Drive 1,800 mi in 30 h

ella [17]

1800 mi / 30 hr = 60 mi/hr

hope that helped

6 0

3 years ago

Two competing headache remedies claim to give fast-acting relief. An experiment was performed to compare the mean lengths of tim

DaniilM [7]

Answer:

$t = 0.875$

Step-by-step explanation:

Given

Brand A Brand B

$n_ 1= 12$ $n_2 = 12$

$\bar x_1 = 21.8$ $\bar x_2 = 18.9$

$\sigma_1 = 8.7$ $\sigma_2 = 7.5$

Required

Determine the test statistic (t)

This is calculated as:

$t = \frac{\bar x_1 - \bar x_2}{s\sqrt{\frac{1}{n_1} + \frac{1}{n_2}}}$

Calculate s using:

$s = \sqrt{\frac{(n_1-1)*\sigma_1^2+(n_2-1)*\sigma_2^2}{n_1+n_2-2}}$

The equation becomes:

$s = \sqrt{\frac{(12-1)*8.7^2+(12-1)*7.5^2}{12+12-2}}$

$s = \sqrt{\frac{1451.34}{22}}$

$s = \sqrt{65.97}$

$s = 8.12$

So:

$t = \frac{\bar x_1 - \bar x_2}{s\sqrt{\frac{1}{n_1} + \frac{1}{n_2}}}$

$t = \frac{21.8 - 18.9}{8.12 * \sqrt{\frac{1}{12} + \frac{1}{12}}}$

$t = \frac{21.8 - 18.9}{8.12 * \sqrt{\frac{1}{6}}}$

$t = \frac{21.8 - 18.9}{8.12 * 0.408}}$

$t = \frac{2.9}{3.31296}}$

$t = 0.875$

3 0

3 years ago

Solve for k.

Alex Ar [27]

k= 4/9 or 0.444 in decimal form.

hope this helps!

5 0

3 years ago

Read 2 more answers

A bag of marbles contains 4 red

marissa [1.9K]

The answer is 7/8!!!!!!

6 0

3 years ago

Help ASAP also Pls put explanation along with answer (#7)

uysha [10]

I first think that you need to do 64 squared which is 8 then add the other 8 then you have 16 then do 16 square which equals 4 then I think you do 4 x 3 then add 25 then you get your answer..... hopefully

8 0

3 years ago