Log₄20-log₄ 45+log₄144=
log₄(20/45)+log₄144= (log_a b- log_a c=log_a (b/c) )
log₄[(20*144)/45]= (log_a b +log_a c=log_a (b*c) )
log₄(2880/45)=
log₄(64)=n ⇔ 4^n=64 (log_a x=n ⇔ a^n=x)
4^n=4³ ⇒n=3 (64=4*4*4=4³)
Answer: log₄20-log₄ 45+log₄144=3
Joint Frequency because of the fact that it "joins" one number from the column(up and down) and one from the row(side-by-side), hence the two-way table.
No,27.93 equals <span>20.00+7.00+0.9+0.03</span>
The density of the gold is 772.8 kilograms\cubic meters
Answer:
If this is the complete question them the answer is 1250 m²
Step-by-step explanation:
the pool in the drawing is 15x7.5 and the scale is 3/1000 so if the size in the drawing is 3 then the actual is 1000.
x=15*1000/3=5000cm which would be 50m
x=7.5*1000/3=2500cm which is 25m
the actual area of the pool is 50*25=1250 m²