we are given
we have to find theta
so, firstly we can write sin in terms of cos
now, we can set it equal
Since, both sides are cos
so, we can set angles equal
now, we can solve for theta
we get
..............Answer
Answer:
3.844 x 10 to the power of 5 is the answer i think
Step-by-step explanation:
so after the 10 non soloists join, there would be 60 students total and 12 of them are soloists.
12 is 20% of 60
Final Answer:
20% of the choir are soloists.
Hope this helped!
Have an awesome day :)
Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
