C metal. most metals are a conductor which an electric current is attracted to.
Answer:
<h2>42.67N</h2>
Explanation:
Step one:
<u>Given </u>
mass m= 0.32kg
intital velocity, u= 14m/s
final velocity v= 22m/s
time= 0.06s
Step two:
<u>Required</u>
Force F
the expression for the force is
F=mΔv/t
F=0.32*(22-14)/0.06
F=(0.32*8)/0.06
F=2.56/0.06
F=42.67N
The average force exerted on the bat 42.67N
Answer:
Minimum capacitance = 200 μF
Explanation:
From image B attached, we can calculate the current flowing through the capacitors.
Thus;
Since V=IR; I = V/R = 5/500 = 0.01 A
Maximum charge in voltage is from 5V to 4.9V. Thus, each capacitor will have 2.5V. Hence, change in voltage(Δv) for each capacitor will be ; Δv = 0.05 V
So minimum capacitance will be determined from;
i(t) = C(dv/dt)
So, C = i(t)(Δt/Δv) = 0.01[0.001/0.05]
C = 0.01 x 0.0002 = 200 x 10^(-6) F = 200 μF
Complete Question
A boy throws a ball on a spring scales which oscillates about the equilibrium position with a period of T = 0.5 sec. The amplitude of the vibration is A = 2 cm. Assume the ball does not bounce from the scales’s surface afterwards. Assume the vibration of the scale is expressed mathematically as x(t) = Acos(t + ). Find:
a) frequency
b) the maximum acceleration
c) the maximum velocity
Answer:
a
b
c
Explanation:
From the question we are told that
The period is
The amplitude is
The vibration of the scale is
Generally the frequency is mathematically represented as
=>
=>
The maximum acceleration is mathematically represented as
=>
=>
The maximum velocity is mathematically represented as
=>
=>
Answer:
Gravitational potential energy to kinetic energy
Explanation:
In this case you have a case about conservation of energy.
When the mass is released and allowed to fall, its energy is completely gravitational potential energy with a value of U = mgh. m is the mass, g is the gravitational constant and h is the height to the floor from the mass.
While the mass is falling down part of its potential energy converts to kinetic energy of value K=1/2mv^2, because the mass has been acquiring more and more velocity.
Thus, the kinetic energy is increasing while the potential energy is decreasing.
When the mass is just above the floor (the moment just before the mass hits the floor) all its potential energy has been converted to kinetic energy.
Then, you have that the kinetic energy of the mass when the mass is just above the floor, is equal to the potential energy when the mass is at height of h. That is:
This is how the law of conservation of energy is fulfilled.