A student swings a container of water in a vertical circle of radius 1.0 m. Calculate the minimum speed of the container so that

Question

2 years ago

6

the water remains in the container at the top of the circle. ANS. 3.1 m/s E-4, P-12?

1 answer:

12345 [234] · Answer 1 · 2022-04-19T12:07:07+03:00

6 0

Answer:

Explanation:

The centripetal acceleration requirement must equal gravity at the top of the circle

mg = mv²/R

v = √Rg

v = √(1.0(9.8))

v = 3.1304951...

v = 3.1 m/s