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vodomira [7]
3 years ago
6

A student swings a container of water in a vertical circle of radius 1.0 m. Calculate the minimum speed of the container so that

the water remains in the container at the top of the circle. ANS. 3.1 m/s E-4, P-12?​
Physics
1 answer:
12345 [234]3 years ago
6 0

Answer:

Explanation:

The centripetal acceleration requirement must equal gravity at the top of the circle

mg = mv²/R

  v = √Rg

  v = √(1.0(9.8))

  v = 3.1304951...

  v = 3.1 m/s

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inysia [295]
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Changing electric and magnetic fields applied at right angles

Radio waves are transverse wave, which means  that the oscillations occurring perpendicular to the direction of energy transfer

hope this helps
3 0
3 years ago
Use newton's method to find the second and third approximation of a root of
Nina [5.8K]
Please answer this question 

5 0
3 years ago
An electron enters the gap between the plates of a capacitor at the center of the gap traveling parallel to theplates at 2.0 x 1
Svetlanka [38]

Answer:

How far will the electron travel beforehitting a plate is 248.125mm

Explanation:

Applying Gauss' law:

Electric Field E = Charge density/epsilon nought

Where charge density=1.0 x 10^-6C/m2 & epsilon nought= 8.85× 10^-12

Therefore E = 1.0 x 10^-6/8.85× 10^-12

E= 1.13×10^5N/C

Force on electron F=qE

Where q=charge of electron=1.6×10^-19C

Therefore F=1.6×10^-19×1.13×10^5

F=1.808×10^-14N

Acceleration on electron a = Force/Mass

Where Mass of electron = 9.10938356 × 10^-31

Therefore a= 1.808×10^-14 /9.11 × 10-31

a= 1.985×10^16m/s^2

Time spent between plate = Distance/Speed

From the question: Distance=1cm=0.01m and speed = 2×10^6m/s^2

Therefore Time = 0.01/2×10^6

Time =5×10^-9s

How far the electron would travel S =ut+ at^2/2 where u=0

S= 1.985×10^16×(5×10^-9)^2/2

S=24.8125×10^-2m

S=248.125mm

4 0
3 years ago
Which two elements have the same number of valence electrons?
UNO [17]

Answer:

The answer is A. C and O..

4 0
3 years ago
Read 2 more answers
A sample of chloroform is found to contain 12.0 g of carbon, 106.4 g of chlorine, and 1.01 g of hydrogen. If a second sample of
GREYUIT [131]

Given:

Sample 1:

Chloroform is CHCl_{3}

12 g Carbon

1.01 g Hydrogen

106.4 g Cl

Sample 2:

30.0 g of Carbon

Solution:

mass of chloroform from sample 1:

12 + 1.01 +106.4 =119.41 g

Now, for the total mass of chloroform in sample 2:

mass of chloroform \times\frac{given mass of carbon}{mass of carbon atom}

mass of chloroform = 119.41 \times\frac{30}{12} = 298.53 g

6 0
3 years ago
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