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Lady_Fox [76]
3 years ago
9

calculate the density of a neutron star with a radius 1.05 x10^4 m, assuming the mass is distributed uniformly. Treat the neutro

n star as a giant ucleaus and consider the mass of a nucleon 1.675 x 10^-27 kg. Your answer should be in the form of N x 10^17 kg/m^3. Enter onlt the number N with teo decimal places, do not enter unit.
Physics
1 answer:
Orlov [11]3 years ago
4 0

To develop this problem it is necessary to apply the concepts related to the proportion of a neutron star referring to the sun and density as a function of mass and volume.

Mathematically it can be expressed as

\rho = \frac{m}{V}

Where

m = Mass (Neutron at this case)

V = Volume

The mass of the neutron star is 1.4times to that of the mass of the sun

The volume of a sphere is determined by the equation

V = \frac{4}{3}\pi R^3

Replacing at the equation we have that

\rho = \frac{1.4m_{sun}}{\frac{4}{3}\pi R^3}

\rho = \frac{1.4(1.989*10^{30})}{\frac{4}{3}\pi (1.05*10^4)^3}

\rho = 5.75*10^{17}kg/m^3

Therefore the density of a neutron star is 5.75*10^{17}kg/m^3

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agasfer [191]

Answer:

The frequency of the photon is 3.069\times10^{14}\ Hz.

Explanation:

Given that,

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We need to calculate the energy

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4h\nu-2h\nu=4.07\times10^{-19}

\nu=\dfrac{4.07\times10^{-19}}{2h}

Put the value of h into the formula

\nu=\dfrac{4.07\times10^{-19}}{2\times6.63\times10^{-34}}

\nu=3.069\times10^{14}\ Hz

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3 years ago
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timurjin [86]
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3 years ago
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Explanation:

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