Answer:
12.0 meters
Explanation:
Given:
v₀ = 0 m/s
a₁ = 0.281 m/s²
t₁ = 5.44 s
a₂ = 1.43 m/s²
t₂ = 2.42 s
Find: x
First, find the velocity reached at the end of the first acceleration.
v = at + v₀
v = (0.281 m/s²) (5.44 s) + 0 m/s
v = 1.53 m/s
Next, find the position reached at the end of the first acceleration.
x = x₀ + v₀ t + ½ at²
x = 0 m + (0 m/s) (5.44 s) + ½ (0.281 m/s²) (5.44 s)²
x = 4.16 m
Finally, find the position reached at the end of the second acceleration.
x = x₀ + v₀ t + ½ at²
x = 4.16 m + (1.53 m/s) (2.42 s) + ½ (1.43 m/s²) (2.42 s)²
x = 12.0 m
Answer:
Positively charged objects have electrons; they simply possess more protons than electrons.
Explanation:
2. An object that is electrically neutral contains only neutrons. Electrically neutral atoms simply possess the same number of electrons as protons.
<h3>Information:</h3>
If an atom has an equal number of protons and electrons, its net charge is 0. If it gains an extra electron, it becomes negatively charged and is known as an anion.
<h3>Tips:</h3>
If it loses an electron, it becomes positively charged and is known as a cation.
<h2>I hope this answers help you! :></h2>
Answer:
-150 kg m/s
Explanation:
The change of momentum is calculated as ;
Δp= m*Δv where
where
Δp= change in momentum
Δv = vf-vi
m= mass of the object
Change in momentum is also calculated when using the formula;
Δp = F * Δt when F is the net force applied and Δt is the time of action.
In this case;
m= 15 kg
vf= -10 m/s
vi= 0 m/s
Taking rightward direction to be positive, then leftward will be negative.
Applying the formula as;
Δp = m*Δv
Δp = 15 * { -10 -0} = 15*-10 = -150 kg m/s
I’m pretty sure it’s D. variable
Since the car is driven 125km west and then 65km north, we simply add the two values together to get 190km
