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adoni [48]
2 years ago
15

Write the phrase as an expression. Then evaluate when x=5.

Mathematics
1 answer:
arlik [135]2 years ago
8 0
The value of the expression when x= 5 is 3

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PLEASE HELPP! Question 1: Factorise each of the following (a) x² + 7x + 12 (b) x² + 6x + 8 (c) x² + 5x + 6 (d) x² + 8x + 7
Liula [17]

Answer:

<em><u>Using the mid-term break formula for all of them.</u></em>

a) x²+7x+12

= x²+3x+4x+12

= x(x+3)+4(x+3)

= (x+4)(x+3)

b) x²+6x+8

= x²+2x+4x+8

= x(x+2)+4(x+2)

= (x+4)(x+2)

c) x²+5x+6

= x²+2x+3x+6

= x(x+2)+3(x+2)

= (x=3)(x+2)

d) x²+8x+7

= x²+7x+x+7

= x(x+7)+1(x+7)

= (x+1)(x+7)

6 0
4 years ago
Read 2 more answers
The half life of uranium-232 is 68.9 years. (show step by step)
dalvyx [7]

Answer:

1.) 8.09g ; 2) 206.7 years

Step-by-step explanation:

Given the following :

Half-life(t1/2) of Uranium-232 = 68.9 years

a) If you have a 100 gram sample, how much would be left after 250 years?

Initial quantity (No) = 100g

Time elapsed (t) = 250 years

Find the quantity of substance remaining (N(t))

Recall :

N(t) = No(0.5)^(t/t1/2)

N(250) = 100(0.5)^(250/68.9)

N(250) = 100(0.5)^3.6284470

N(250) = 100 × 0.0808590

= 8.0859045

= 8.09g

2) If you have a 100 gram sample, how long would it take for there to be 12.5 grams remaining?

Using the relation :

N / No = (1/2)^n

Where N = Amount of remaining or left

No = Original quantity

n = number of half-lifes

N = 12.5g ; No = 100g

12.5 / 100 = (1/2)^n

0.125 = (1/2)^n

Converting 0.125 to fraction

(1/8) = 1/2^n

8 = 2^n

2^3 = 2^n

n = 3

Recall ;

Number of half life's (n) = t / t1/2

t = time elapsed ; t1/2 = half life

3 = t / 68.9

t = 3 × 68.9

t = 206.7 years

7 0
3 years ago
PLS WAMSER ILL GIVE YOU BRAINLIEST
kotykmax [81]
He will need about 100 in^2
6 0
3 years ago
Graph y= x−2.<br> PLZZ HELP
nataly862011 [7]

Explanation: To graph the equation y = x - 2, the idea is simple.

We pick three values for <em>x</em>, plug them into the

equation, and find the corresponding values for <em>y</em>.

In order to do this in an organized way, we set up a chart.

Down the left side we make a column for our x's, down the right side we make a column for our y's, and in the middle we make a column for the side of the equation that contains the <em>x</em>, in this case, x - 2.

So reading the chart from left to right, we have our <em>x</em> or what we plug into the equation, then we have the x - 2 or what happens to the x when we plug it into the equation, and finally we have our <em>y</em> or what we end up with after plugging <em>x</em> into the equation.

So our first step in filling out the chart is choosing

the x's that we want to plug into the equation.

When graphing lines, I always choose three x's,

a positive number, zero, and a negative number.

The easiest numbers to pick are usually 1, 0, and -1.

So for 1, we plug a 1 into the equation for <em>x</em>

and we have y = (1) - 2 or -1

For 0 we plug a 0 into the equation for <em>x</em>

and we have y = (0) - 2 or -2.

For -1 we plug a -1 into the equation for <em>x</em>

and we have y = (-1) - 2 or -3.

So our points are (1, -1), (0, -2), and (-1, -3).

I looked at the x and y column to find those points.

Since our domain is all real numbers, we can connect these points based on the pattern that they are forming on the graph which is a line.

5 0
3 years ago
Read 2 more answers
Solve the following system of equations using the elimination method. 2x + 4y = 10 –2x + y = –15
pychu [463]

Answer:

(7, - 1 )

Step-by-step explanation:

Given the 2 equations

2x + 4y = 10 → (1)

- 2x + y = - 15 → (2)

Adding the 2 equations term by term eliminates the term in x, that is

5y = - 5 ( divide both sides by 5 )

y = - 1

Substitute y = - 1 into either of the 2 equations and solve for x

Substituting into (1)

2x + 4(- 1) = 10

2x - 4 = 10 ( add 4 to both sides )

2x = 14 ( divide both sides by 2 )

x = 7

Solution is (7, - 1 )

6 0
4 years ago
Read 2 more answers
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