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V125BC [204]
2 years ago
12

Please help me?i don’t want to fail

Mathematics
1 answer:
Kobotan [32]2 years ago
8 0

Answer:

8.

<u>9y-3y=6</u>

-4x-(-5x)=1

the slope is 6

9.

you start at the 0 axis and go up 3 on the y.Once you did that you want to go up 2 on the y axis then 3 to the right on the x axis,then go up 2 then 3 to the right.

Step-by-step explanation:

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Karen drove her car 15 miles and used 2 gallons of gas she wants to know how many gallons she will use if she has to drive 75 mi
Airida [17]

Answer:

10 gallons of gas

Step-by-step explanation:

Create a proportion, where x is the number of gallons she will use if she drives 75 miles:

\frac{15}{2} = \frac{75}{x}

Cross multiply and solve for x:

15x = 150

x = 10

So, she will have to use 10 gallons of gas to drive 75 miles

5 0
3 years ago
Read 2 more answers
What distance from Earth to the moon is about 22 to the 4power miles. The distance from Earth to Neptune is about 22 to the 7pow
nalin [4]
The distance to Neptune is greater.
It is about  10 to the 3rd power (1,000) times greater.
7 0
3 years ago
The parking space shown at the right has an area of 209 ft2. A custom
jeyben [28]

Given:

The parking space shown at the right has an area of 209 ft².

A custom truck has rectangular dimensions of 13.5 ft by 8.5 ft.

To find:

Whether the truck fit in the parking space or not?

Solution:

If the area of the truck is more than the area of the parking space, then the truck cannot fit in the parking space otherwise it will fit in the parking space.

The area of a rectangle is:

Area=length\times width

Area of the rectangular truck is:

Area=13.5\times 8.5

Area=114.75

The area of the truck is 114.75  ft² which is less than the area of the parking space, 209 ft².

Therefore, the truck can fit in the parking space because the area of the truck is less than the area of the parking space.

3 0
3 years ago
You are riding along a straight river from east to the west at speed of 160m/m. At a given time, you will see the bearing of a c
yuradex [85]

Using the given information, the width of the river is 505.96 m

<h3>Bearing and Distances</h3>

From the question, we are to determine the width of the river

Consider the given diagram,

Let F be the first position of the biker

S be the second position

and C be the position of the church

First, we will determine the distance covered from F to S

Speed = 160m/min

Time = 4 minutes

Using the formula,

Distance = Speed × Time

Distance covered = 160 × 4

Distance covered = 640 m

That is, /FS/ = 640 m

Now, consider ΔFSC

∠F = 90° - 70° = 20°

∠S = 90° + 56° = 146°

and ∠C = 180° - 20° - 146° = 14°

By the Law of Sines

\frac{/FC/}{sin\ S}= \frac{/FS/}{sin\ C}

∴ \frac{/FC/}{sin\ 146^\circ}= \frac{640}{sin\ 14^\circ}

/FC/ =\frac{640 \times sin \ 146^\circ}{sin \ 14^\circ}

/FC/ = 1479.33 m

Now,

By SOH CAH TOA

cos \ 70^\circ = \frac{d}{/FC/}

NOTE: d is the width of the river

∴ d = /FC/ × cos70°

d = 1479.33 × cos70°

d = 505.96 m

Hence, the width of the river is 505.96 m

Learn more on Bearing and distances here: brainly.com/question/19351991

#SPJ1

7 0
2 years ago
What is .194 with the 94 repeating as a fraction?
LekaFEV [45]
Your answer is 97/500. I hope this has helped
4 0
3 years ago
Read 2 more answers
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