Are you trying to figure out what's x?
Answer:
C
=
(
a
,
b
)
the center coordinates of circle
a
=
2
,
b
=
−
1
,
r
=
8
Step-by-step explanation:
Removing parentheses.
Subtract 0.02m from -0.1m to get -0.12m
Answer -
".02mn-0.12m-0.2"
Answer:
![b = (q,r , 5q-2\sqrt{26} )](https://tex.z-dn.net/?f=b%20%20%3D%20%20%28q%2Cr%20%2C%205q-2%5Csqrt%7B26%7D%20%29)
Step-by-step explanation:
From the question we are told that
The vector given is
![a = (5,0,-1)](https://tex.z-dn.net/?f=a%20%3D%20%285%2C0%2C-1%29)
Also ![comp_a b = 2](https://tex.z-dn.net/?f=comp_a%20b%20%3D%20%202)
Generally
![comp_a b = \frac{a \cdot b}{|a|}](https://tex.z-dn.net/?f=comp_a%20b%20%20%3D%20%20%5Cfrac%7Ba%20%5Ccdot%20b%7D%7B%7Ca%7C%7D)
Here
is the magnitude of a which is mathematically represented as
![|a| = \sqrt{5^2 + 0^2 +(-1)^2 }](https://tex.z-dn.net/?f=%7Ca%7C%20%3D%20%20%5Csqrt%7B5%5E2%20%20%2B%200%5E2%20%20%2B%28-1%29%5E2%20%7D)
=> ![|a| = \sqrt{26}](https://tex.z-dn.net/?f=%7Ca%7C%20%3D%20%20%5Csqrt%7B26%7D)
b is vector which we will assume to have the following parameters
![b = (q , r , x)](https://tex.z-dn.net/?f=b%20%20%3D%20%20%28q%20%2C%20r%20%2C%20x%29)
So
![comp_a b = \frac{(5,0,-1) \cdot (q,r,x)}{\sqrt{26} } = 2](https://tex.z-dn.net/?f=comp_a%20b%20%3D%20%20%5Cfrac%7B%285%2C0%2C-1%29%20%5Ccdot%20%28q%2Cr%2Cx%29%7D%7B%5Csqrt%7B26%7D%20%7D%20%3D%20%202)
=> ![\frac{5q + 0 -x}{\sqrt{26} } = 2](https://tex.z-dn.net/?f=%5Cfrac%7B5q%20%2B%200%20-x%7D%7B%5Csqrt%7B26%7D%20%7D%20%3D%202)
=> ![x = 5q-2\sqrt{26}](https://tex.z-dn.net/?f=x%20%3D%20%205q-2%5Csqrt%7B26%7D)
Hence the vector be can be mathematically represented as
![b = (q,r , 5q-2\sqrt{26} )](https://tex.z-dn.net/?f=b%20%20%3D%20%20%28q%2Cr%20%2C%205q-2%5Csqrt%7B26%7D%20%29)
This means that the vector b is more than one value since it is made up of variable
This means that if
![q = 1\\r=1\\x =1](https://tex.z-dn.net/?f=q%20%3D%201%5C%5Cr%3D1%5C%5Cx%20%3D1)
Then
![b = (1,1,5-2\sqrt{26} )](https://tex.z-dn.net/?f=b%20%20%3D%20%20%281%2C1%2C5-2%5Csqrt%7B26%7D%20%29)