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Talja [164]
2 years ago
5

Find x to the nearest hundreths

Mathematics
2 answers:
7nadin3 [17]2 years ago
5 0

I'd say the answer is C.

Dimas [21]2 years ago
3 0

\sin 40^{\circ} = \dfrac{x}{16}\\\\ \ \implies x = 16\sin 40^{\circ} =10.28 ~ \text{units.}

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PLEASE HELP WITH EASY MATH
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The constant of proportionality is $1.5 per jar of sauce. Hope it help!
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<img src="https://tex.z-dn.net/?f=%20%7C2v%7C%20%20%3D%2012" id="TexFormula1" title=" |2v| = 12" alt=" |2v| = 12" align="absmi
BlackZzzverrR [31]

Answer:

v=6

Step-by-step explanation:

2v is positive so keep it

then 2v=12

v=6

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olivia has 430 seconds of excercise left. how many complete sets of jumping jacks should she be able to finish
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<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al
Furkat [3]

Answer:  \frac{\sqrt[4]{10xy^3}}{2y}

where y is positive.

The 2y in the denominator is not inside the fourth root

==================================================

Work Shown:

\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\

The idea is to get something of the form a^4 in the denominator. In this case, a = 2y

To be able to reach the 16y^4, your teacher gave the hint to multiply top and bottom by 2y^3

For more examples, search out "rationalizing the denominator".

Keep in mind that \sqrt[4]{(2y)^4} = 2y only works if y isn't negative.

If y could be negative, then we'd have to say \sqrt[4]{(2y)^4} = |2y|. The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

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2 years ago
What is the volume of the prism?<br> 3 m<br> mº<br> 13 m<br> 13 m
NARA [144]
13 m is the volume of the prism
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