Question

Pyramid A is a square pyramid with a base side length of 18 inches and a height of 9 inches. Pyramid B has a volume of 3,136 cubic inches. How many times bigger is the volume of pyramid B than pyramid A? Give your answer as a percentage. Provide an explanation and proof for your answer to receive full credit.

Answer 1

The Volume of Pyramid B is 222.6% bigger than the volume of Pyramid A.

Recall:

• The volume of a square pyramid is given as: $V = a^2\frac{h}{3}$

• Where, a = base edge; h = height

Thus:

Given that Pyramid A has: a = 18 inches; h = 9 inches

Volume = $V = 18^2(\frac{9}{3})$

Volume of Pyramid A = 972 in.³

Volume of Pyramid B = 3,136 in.³

Difference in Volume of both pyramids = 3,136 in.³ - 972 in.³ = 2,164

• This means that: $\frac{2,164}{972} \times 100 = 222.6 \%$ (Pyramid B is 222.6% bigger than Pyramid A)

Learn more about volume of pyramid here:

brainly.com/question/14332950

Answer 2

Answer:

the volume if a square pyramid is V=a2 h/3               ( A = base edge, H = height)

The pyramid has 18 inch of base side length and 9 inches in height. 

thus V = 182  (9/3)

V= 324(3)

V= 972

Volume of pyramid B: 3,136.

3,136 - 972 = 2,164

To find the percentage of these numbers, we must divide them into each other and then multiple them by 100.

2,164/ 972  x 100 

2.22633744856 x 100 

= 222.633744856

Pyramid A is 222.6% bigger than pyramid A

Step-by-step explanation: