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2 years ago

PLEASE PLEASE PLEASE!!!! I NEED HELP

Mathematics

1 answer:

BartSMP [9]2 years ago

3 0

Answer:

Step-by-step explanation:

y = 7x + 13

y = 3x + 49

================

We can solve this in either of two ways: Mathematically and graphically.

Set the equations equal to each other (after all, y does equal y).

7x + 13 = 3x + 49

4x = 36

x = 9

Then use x = 9 to solve for y:

y = 7x + 13

y = 7(9) + 13

x = 76

<h2><u>Graph</u></h2>

Plot the two equations. I use Desmos - its online and free. The intersection of the two lines reveals to answer: (9,76). See the attachment.

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Find the coordinates of the circumcenter of the triangle with the given vertices. X(-2, 1), Y(2, -3), Z(6, -3).

lana [24]

Answer:

C (4,3)

Step-by-step explanation:

Steps to find the circumcenter:

1) Find and Calculate the midpoint of given coordinates or midpoints.

2) Calculate the slope of the perpendicular bisector lines

3) By using the midpoint and the slope, find out the equation of the line

$( y-y_1 )= m(x-x_1)$

4) Do the same for another line

Solve the equations of two lines to get the intersection point.

The intersection point will be the circumcenter of the triangle.

Given :

X(-2,1), Y(2,-3), Z(6,-3)

Please see the attached file:

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3 years ago

The figure show the dimensions of a city park in feet.

Soloha48 [4]

Answer:

73,084

Step-by-step explanation:

3 0

3 years ago

Buddy has 3 $1.00 bills.5 quarters and 4 dimes He sent 3.70 on lunch how much money does he have left

evablogger [386]

Answer:

He started with $4.65.

so 4.65-3.70= .95

Buddy has $0.95 left.

Hope this helps! Please mark as brainliest!!! xx :)

Have a fantastic day!!

Step-by-step explanation:

6 0

4 years ago

Solve: 0 <img src="https://tex.z-dn.net/?f=%5Cleq" id="TexFormula1" title="\leq" alt="\leq" align="absmiddle" class="latex-formu

Salsk061 [2.6K]

$\huge{ \mathrm{ \underline{ Answer }}}࿐$

$6 \sin(x) - 3 \sqrt{2} = 0$

$6 \sin(x) = 3 \sqrt{2}$

$\sin(x) = \dfrac{3 \sqrt{2} }{6}$

$\sin(x) = \dfrac{ \sqrt{2} }{2}$

$\sin(x) = \dfrac{1}{ \sqrt{2} }$

$\large\boxed{x = 45° \: \: or \: \: 135°}$

$\#TeeNForeveR$

6 0

3 years ago

. A box in a certain supply room contains four 40-W lightbulbs, five 60-W bulbs, and six 75-W bulbs. Suppose that three bulbs ar

yaroslaw [1]

Answer:

a) 59.34%

b) 44.82%

c) 26.37%

d) 4.19%

Step-by-step explanation:

(a)

There are in total <em>4+5+6 = 15 bulbs</em>. If we want to select 3 randomly there are K ways of doing this, where K is the<em> combination of 15 elements taken 3 at a time </em>

$K=\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455$

As there are 9 non 75-W bulbs, by the fundamental rule of counting, there are 6*5*9 = 270 ways of selecting 3 bulbs with exactly two 75-W bulbs.

So, the probability of selecting exactly 2 bulbs of 75 W is

$\frac{270}{455}=0.5934=59.34\%$

(b)

The probability of selecting three 40-W bulbs is

$\frac{4*3*2}{455}=0.0527=5.27\%$

The probability of selecting three 60-W bulbs is

$\frac{5*4*3}{455}=0.1318=13.18\%$

The probability of selecting three 75-W bulbs is

$\frac{6*5*4}{455}=0.2637=26.37\%$

Since <em>the events are disjoint</em>, the probability of taking 3 bulbs of the same kind is the sum 0.0527+0.1318+0.2637 = 0.4482 = 44.82%

(c)

There are 6*5*4 ways of selecting one bulb of each type, so the probability of selecting 3 bulbs of each type is

$\frac{6*5*4}{455}=0.2637=26.37\%$

(d)

The probability that it is necessary to examine at least six bulbs until a 75-W bulb is found, <em>supposing there is no replacement</em>, is the same as the probability of taking 5 bulbs one after another without replacement and none of them is 75-W.

As there are 15 bulbs and 9 of them are not 75-W, the probability a non 75-W bulb is $\frac{9}{15}=0.6$

Since there are no replacement, the probability of taking a second non 75-W bulb is now $\frac{8}{14}=0.5714$

Following this procedure 5 times, we find the probabilities

$\frac{9}{15},\frac{8}{14},\frac{7}{13},\frac{6}{12},\frac{5}{11}$

which are

0.6, 0.5714, 0.5384, 0.5, 0.4545

As the events are independent, the probability of choosing 5 non 75-W bulbs is the product

0.6*0.5714*0.5384*0.5*0.4545 = 0.0419 = 4.19%

3 0

3 years ago