Answer:
the entropy change for the surroundings when 1.68 moles of Fe2O3(s) react at standard conditions = 49.73 J/K.
Explanation:
3Fe2O3(s) + H2(g)-----------2Fe3O4(s) + H2O(g)
∆S°rxn = n x sum of ∆S° products - n x sum of ∆S° reactants
∆S°rxn = [2x∆S°Fe3O4(s) + ∆S°H2O(g)] - [3x∆S°Fe2O3(s) + ∆S°H2(g)]
∆S°rxn = [(2x146.44)+(188.72)] - [(3x87.40)+(130.59)] J/K
∆S°rxn = (481.6 - 392.79) J/K =88.81J/K.
For 3 moles of Fe2O3 react, ∆S° =88.81 J/K,
then for 1.68 moles Fe2O3 react, ∆S° = (1.68 mol x 88.81 J/K)/(3 mol) = 49.73 J/K the entropy change for the surroundings when 1.68 moles of Fe2O3(s) react at standard conditions.
Electrons can become excited if it is given extra energy
Exampes:
⁻absorbs a photon
⁻absorbs packet of light
⁻absorbs collides wit nearby atom
⁻absorbs particles.
Earthquakes happen at Transform boundaries
Here are the energy profile diagrams, p.s. sorry couldn’t find any plain paper!
Answer:
The greenhouse effect
Explanation:
The greenhouse effect is a straightforward method that heats the Earth's exterior. When the Sun's rays touch the Earth's environment, some of it is bounced back to space and the rest is grasped and re-heated by greenhouse gases. The consumed energy heats the environment and the exterior of the Earth.