Answer:
w₁ = 0 J
w₂ = -297 J
Explanation:
Step 1: Given data
Initial volume: 266 mL (0.266 L)
Final volume: 983 mL (0.983 L)
Step 2: Calculate the work done (in joules) by the gas if it expands against a vacuum
We will use the following expression.
w₁ = -P₁ × ΔV
Since the gas expands against a vacuum, P₁ = 0. Thus, w₁ = 0 J
Step 3: Calculate the work done (in joules) by the gas if it expands against a constant pressure of 4.09 atm
We will use the following expression.
w₂ = -P₂ × ΔV
w₂ = -4.09 atm × (0.983 L-0.266 L) = -2.93 atm.L
Then, we convert w₂ to Joule using the conversion factor 1 atm.L = 101.325 J.
-2.93 atm.L × 101.325 J/1 atm.L = -297 J
Answer:
To the right
Explanation:
Step 1: Given data
- Partial pressure of PCl₅ (pPCl₅) = 0.548 atm
- Partial pressure of PCl₃ (pCl₃) = 0.780 atm
- Partial pressure of Cl₂ (pCl₂) = 0.780 atm
Step 2: Write the balanced equation
PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)
Step 3: Calculate the pressure reaction quotient
Step 4: Determine whether the reaction proceeds to the right or to the left as equilibrium is approached
Since <em>Qp < Kp</em>, the reaction will proceed to the right to attain the equilibrium.
<span>True. In chemistry, mixtures are two (or more) substances mixed together but not combined chemically. This means there are no chemical bonds that have formed between the substances. As such, they can be separated with physical processes.</span>
Answer: 0.18 M
Explanation:
Initial molarity, M1 = 0.8 M
Initial olume, V1 = 225 ml
Final volume, V2 = 1000 ml
Final Molarity, M2 = M1V1/V2
= 0.8 x 225/1000
= 0.18 M
