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Pavel [41]
3 years ago
12

How do you find out if the inverse of a piece wise function is a function?

Mathematics
1 answer:
cricket20 [7]3 years ago
8 0

Answer:

If it is not one-to-one, it does not have an inverse.

Step-by-step explanation:

If the output has more than 1 input, it cannot possibly be a function, meaning there is no inverse for that function.

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What postulate or theorem proves the two triangles are similar?
Keith_Richards [23]

Answer:sas

Step-by-step explanation:

6 0
3 years ago
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The area of a circle is 153.86 square meters. What is the diameter of the circle?
Yuliya22 [10]
Area of circle = πr² 

Given that area = 153.86 m², find the radius:

 153.86 = πr²

r² = 153.86 ÷ π

r² = 48.98

r = √48.98

r = 7 m

Diameter = Radius x 2 = 7 x 2 = 14 m

Answer: Diameter = 14 m



8 0
3 years ago
Bob and Carl each renter the same kind of moving truck from ez move. There was a flat rental fee plus charge per mile that the t
dimulka [17.4K]

It's a linear function: y = mx + b

We have (138; 112.96); (209; 142.78)

substitute the values of x and y to the formula of slope m:

m=\dfrac{y_2-y_1}{x_2-x_1}\\\\m=\dfrac{142.78-112.96}{209-138}=0.42

Now we have: y=0.42x+b

We must find b. Substitute the value of x and y from first pair of numbers:

112.96=0.42\cdot138+b\\\\112.96=57.96+b\ \ \ |-57.96\\\\b=55

Answer: y = 0.42x + 55

3 0
3 years ago
Read 2 more answers
Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.
mart [117]

Answer:

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

Step-by-step explanation:

The given expression is  

\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}    [\because a^ma^n=a^{m+n}]

\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}

\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}         [\because a^{-n}=\dfrac{1}{a^n}]

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

5 0
4 years ago
Simplify the rational expression 6x(x+3)(x-2)/3(x-2)(x+9) A) 2x/x-3 B)2x/(x-9) C) 2x(x+3)/(x+9)
Irina-Kira [14]

Answer:

\large\boxed{C)\ \dfrac{2x(x+3)}{(x+9)}}

Step-by-step explanation:

\dfrac{6x(x+3)(x-2)}{3(x-2)(x+9)}=\dfrac{6\!\!\!\!\diagup^2}{3\!\!\!\!\diagup_1}\cdot\dfrac{(x-2)}{(x-2)}\cdot\dfrac{x(x+3)}{(x+9)}=\dfrac{2x(x+3)}{(x+9)}

6 0
3 years ago
Read 2 more answers
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