Since you have a angle number of 23 and you see the tiny square that means it’s equal to 90 up top and add 23 and 90 together and then subtract that by 180 to get all 3 angles in the triangle and then just use that to find the other line that’s 180.
Answer:
B.) 6
2.) 70
3.) 56
Step-by-step explanation:
B.) 2(6) - 6
= 12 - 6
=6
2.) 7(2(3)+4)
=7(6+4)
=42+28
=70
3.) 10(3) + 4(3) + 14
= 30 + 12 + 14
= 42+14
=56
Have a wonderful day
:)
Answer:
a = 1565217.39 ft / s ^ 2
t = 0.001725 seconds
Step-by-step explanation:
The first thing is to use the same system of units therefore we will pass the 28 inches to feet, like this:
28 in * (1 ft / 12 in) = 2.33 ft
Now yes, we can continue, we have the following data:
vi = 0
vf = 2700 ft / s
the equations in this case are as follows:
vf = vi + a * t
vf = a * t
rearranging for a
a = vf / t (1)
now with the position equation we know that:
x = vi * t + (a * t ^ 2) / 2
x = (a * t ^ 2) / 2 (2)
now replacing (1) in (2), we are left with:
x = (vf / t) * (t ^ 2) / 2
knowing that x would be 2.33 ft, which is when the cannonball exits the cannon.
2.33 = 2700 * t / 2
t = 2.33 * 2/2700 = 0.001725 seconds.
and now replace in (1)
a = vf / t = 2700 / 0.001725 = 1565217.39 ft / s ^ 2
Answer: 26
There’s nothing here for me to solve
