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lidiya [134]
3 years ago
11

It cost Joseph $21.90 to send 146 text messages. How many text messages did he send if he spent $6.45?

Mathematics
1 answer:
Margarita [4]3 years ago
7 0

Answer:

43 messages

Step-by-step explanation:

Given:

146 messages = $21.90

x messages = $6.45

Finding x by cross-multiplication:

x = 146*6.45/21.90 = 43

Hope this helps! :)

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Find CE if AE = 8 and BC = 3. Round to the nearest tenth. AE is tangent to the circle. (Hint: May need quadratic formula)
boyakko [2]

The value of CE = 18.3

According to the statement

Here we have given the value of tangents AE = 8 and BC = 3

we have to find the value of CE and

It is given that AE is the tangent to the circle.

Now we make a equation to find the CE then

(8)^2 = 3(x+3)

In this equation the value of AE is 8. and

In this x is the value of CE and BC have value 3.

And the total value of BE becomes the 3(x+3) and 3 is the parts by which  BE is formed.

Then solve the equation

64= 3x +9

3x = 64-9

x = 18.3

So, The value of CE = 18.3

Learn more about TANGENT here brainly.com/question/17040970

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7 0
2 years ago
21 POINTS!<br>Jeff had $20. He spent 3/8 of his money on lunch. How much money does jeff have left?
lara [203]

Answer:

$12.50

Step-by-step explanation:

3/8 x 20/1 = 7.5

20 - 7.5 = 12.50

4 0
3 years ago
What is the area of number 4?
Tanzania [10]

Answer:

<h3>800 cm²</h3>

Step-by-step explanation:

Look at the picture.

We have three rectangles. The formula of an area of a rectangle:

A=lw

l - length

w - width

Rectangle I:

A_I=7\cdot20=140\ cm^2

Rectangle II:

A_{II}=6\cdot20=120\ cm^2

Rectangle III:

A_{III}=18\cdot30=540\ cm^2

The area of number 4:

A=A_{I}+A_{II}+A_{III}

Substitute:

A=140+120+540=800\ cm^2

5 0
3 years ago
A crawling tractor sprinkler is located as pictured below, 100 feet South of a sidewalk. Once the water is turned on, the sprink
deff fn [24]

Answer:

  a) see below

  b) 32 minutes after turn-on

  c) 52 minutes after turn-on

  d) 20 minutes

  e) 6856.6 ft²

Step-by-step explanation:

a) We have elected to put the origin at the point where the hose crosses the south edge of the sidewalk. Units are feet. Then the sprinkler starts at (0, -100). After 1 hour, 3600 seconds, the sprinkler is 1800 inches, or 150 ft north of where it started, so stops at (0, 50).

The lines forming the sidewalk boundaries are y=0 and y=10.

__

b) Water will first strike the sidewalk when the sprinkler is 20 feet south of it, or 80 feet north of where it started. The sprinkler travels that distance in ...

  (80 ft)(12 in/ft)/(1/2 in/s)(1 min/(60 s)) = 32 min . . . time to start sprinkling sidewalk

__

c) The sprinkler has to travel to a point 130 ft north of its starting position for the water to fall north of the sidewalk. That distance is traveled in ...

  (130 ft)(2/5 min/ft) = 52 min . . . time until end of sprinkling sidewalk

Note that we have combined the scale factors in the expression of part b into one scale factor of (2/5 min/ft).

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d) The difference of times in parts b and c is the time water falls on the sidewalk: 20 minutes.

__

e) In one hour, the sprinkler travels a distance of ...

  (60 min)(5/2 ft/min) = 150 ft

Of that distance, 10 feet is sidewalk. So, the sprinkler covers an area of grass that is a 140 ft by 40 ft rectangle and a circle of 20 ft radius. The total area of that is ...

  A = LW + πr² = (140 ft)(40 ft) +π(20 ft)² = (14+π)(400) ft² ≈ 6856.6 ft²

The area of grass watered in 1 hour is about 6856.6 ft².

5 0
4 years ago
Find the missing measure x° 65°
BARSIC [14]
The answer is 25 degrees
4 0
3 years ago
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