$x^2+3x-18=0\\\\x^2+3x=18\\\\\text{We can see the beginning of } (x+\dfrac{3}{2})^2 \\\\x^2+3x=(x+\dfrac{3}{2})^2-\dfrac{3^3}{2^2}=18\\\\(x+\dfrac{3}{2})^2=18+\dfrac{9}{4}=\dfrac{18*4+9}{4}=\dfrac{81}{4}$

Hope this helps.

Thank you.

6 0

3 years ago

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What is the value of x?<br> 4x − 6 = 18

tensa zangetsu [6.8K]

You need to get rid of -6 by adding 6, you also need to add 6 to 18.

4x = 24

Now you need to get rid of the 4 attached to the variable, you do this by dividing 4 since it is multiplying, also dividing 4 and 24

x = 6

So the value of x is 6

Hope this helps! :)

8 0

3 years ago

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What is 74 divided by 9??

Rama09 [41]

Its 8.22.. the 2 repeats

3 0

3 years ago

What's 298,987 divided by 98?​

What's 298,987 divided by 98?