A parallel line has the same slope as the original line. So in this case the slope of the line is also 3/4. Now how do we know if it intersects the point? We need to adjust the y intercept.
Currently, we know the equation of the line is y= 3/4 x + b, where b is the thing we are looking for. We also have a point, which supplies the x and y. Plug that in and solve for b
-2 = (3/4)*(12) + b
You'll get b= -11
So the equation of the parallel line intersecting the point given is y= 3/4x -11.
I am assuming that the slope is 3/4 based on the way you formatted the original equation, but it's the same steps if the slope is different.
125.638 rounded to the nearest hundredth equal 125.64
Answer:
The factorization of 
is 
Step-by-step explanation:
This is a case of factorization by <em>sum and difference of cubes</em>, this type of factorization applies only in binomials of the form 
or 
. It is easy to recognize because the coefficients of the terms are <u><em>perfect cube numbers</em></u> (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).
Let's solve the factorization of by using the <em>sum and difference of cubes </em>factorization.
1.) We calculate the cubic root of each term in the equation , and the exponent of the letter x is divided by 3.
![\sqrt[3]{729x^{15}} =9x^{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B729x%5E%7B15%7D%7D%20%3D9x%5E%7B5%7D)
then ![\sqrt[3]{10^{3}} =10](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B10%5E%7B3%7D%7D%20%3D10)
So, we got that
which has the form of which means is a <em>sum of cubes.</em>
<em>Sum of cubes</em>
with 
y 
2.) Solving the sum of cubes.
.
Answer:
1. Identify the problem: Packaging boxes use too much material and create waste
2. What are the equations for the volume and surface area of a cube and rectangular prism?
Volume of a cube: Vcube = L x L x L = L3
Surface area of a cube: SAcube = 6 x (L x L) = 6L2
Volume of a rectangular prism: VRP = L x W x H = LWH
Surface area of a rectangular prism: SARP = 2 x (L x W) + 2 x (L x H) + 2 x (W x H) = 2(LW + LH + WH)
3. What is the difference in surface area of the packages below? (Note that they have the same volume.)
SAcube = 6L2
= 6 (20 cm)2
= 2,400 cm2
SARP = 2(LW + LH + WH) = 2 (20cm x 10cm + 20cm x 40cm + 10cm x 40cm) = 2,800 cm2
SARP – SAcube = 2,800 cm2
– 2,400cm2
= 400 cm
Step-by-step explanation:
everything in bold is the answer
Can I please get the Brainlist
Answer:
its C
Step-by-step explanation:
