At the bottom of the circle, the ball is being pulled upward by tension in the rope and downward by its own weight, so that the net force on it is
∑ F = 450 N - (0.75 kg) g = (0.75 kg) a
where a is centripetal acceleration. At this maximum tension, the ball has a maximum centripetal acceleration of
a = (450 N - (0.75 kg) g) / (0.75 kg) = 590.2 m/s²
Then its maximum tangential speed v is such that
a = v² / (1.0 m)
⇒ v = √((1.0 m) a) ≈ 25 m/s
Answer: To solve such problems we need to know about Trigonometry.
Trigonometric functions
where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.
The value of x is 5√3.
Explanation: Given to us,
the base for the triangle, AB = 5 units,
Hypotenuse for the triangle, BC = 10 units,
∠B = 60°,
Solution
The question can be solved in two ways,
1. Using the Pythagoras theorem,
According to Pythagoras theorem,
substituting the values,
2. using the trigonometric function for ∠B,
for ∠B in ΔABC,
substituting the values,
we know that value of tan(60°) is √3,
Hence, the value of x is 5√3.
Answer:
the quality of being made up of exactly similar parts facing each other or around an axis. it helps art look precise and exactly the same on both sides
Answer:
2440.24 J
Explanation:
Moment of inertia, I1 = 5 kg m^2
frequency, f1 = 3 rps
ω1 = 2 x π x f1 = 2 x π x 3 = 6 π rad/s
Moment of inertia, I2 = 2 kg m^2
Let the new frequency is f2.
ω2 = 2 x π x f2
here no external torque is applied, so the angular momentum remains constant.
I1 x ω1 = I2 x ω2
5 x 6 π = 2 x 2 x π x f2
f2 = 7.5 rps
ω2 = 2 x π x 7.5 = 15 π
Initial kinetic energy, K1 = 1/2 x I1 x ω1^2 = 0.5 x 5 x (6 π)² = 887.36 J
Final kinetic energy, K2 = 1/2 x I2 x ω2^2 = 0.5 x 3 x (15 π)² = 3327.6 J
Work done, W = Change in kinetic energy = 3327.6 - 887.36 = 2440.24 J
