The radius of a sodium atom is determined as 2.145 x 10⁻⁸ cm.
<h3>
What is body-centered cubic unit cell?</h3>
Body-centered cubic (BCC) is the name given to a type of atom arrangement found in nature.
A body-centered cubic unit cell structure consists of atoms arranged in a cube where each corner of the cube shares an atom and with one atom positioned at the center.
<h3>
Volume of the sodium atom</h3>
The volume of the sodium atom is calculated as follows;
V = ZM/Nρ
where;
- Z is 2 for a body-centered cubic unit cell
- M is mass of sodium atom = 23 g/mol
- ρ is density of sodium atom
- N is Avogadro's number
V = (2 x 23) / (6.023 x 10²³ x 0.968)
V = 7.89 x 10⁻²³ cm³
<h3>Edge length of the unit cell</h3>
a = (V)^¹/₃
a = (7.89 x 10⁻²³ cm³)^¹/₃
a = 4.29 x 10⁻⁸ cm
<h3>Radius of the unit cell</h3>
r = a/2
r = ( 4.29 x 10⁻⁸ cm) / 2
r = 2.145 x 10⁻⁸ cm
Thus, the radius of a sodium atom is determined as 2.145 x 10⁻⁸ cm.
Learn more about sodium atom here: brainly.com/question/25033306
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Explanation:
here's the answer to your question
Answer:
a. 59 m/atm
Explanation:
- To solve this problem, we must mention Henry's law.
- <em>Henry's law states that at a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.</em>
- It can be expressed as: C = KP,
C is the concentration of the solution (C = 1.3 M).
P is the partial pressure of the gas above the solution (P = 0.022 atm).
K is the Henry's law constant (K = ??? M/atm),
∵ C = KP.
∴ K = C/P = (1.3 M)/(0.022 atm) = 59.0 M/atm.