Answer:
69.6 g CO₂
Explanation:
To find the mass of carbon dioxide, you need to (1) convert grams LiOH to moles LiOH (via molar mass from periodic table values), then (2) convert moles LiOH to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (desired unit in the numerator). The final answer should have 3 sig figs to reflect the given value's sig figs.
Molar Mass (LiOH): 6.9410 g/mol + 15.998 g/mol + 1.008 g/mol
Molar Mass (LiOH): 23.947 g/mol
2 LiOH(s) + 1 CO₂(g) ----> Li₂CO₃(s) + H₂O(l)
Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)
Molar Mass (CO₂): 44.007 g/mol
75.8 g LiOH 1 mole 1 mole CO₂ 44.007 g
------------------ x ---------------- x ----------------------- x ------------------- =
23.947 g 2 moles LiOH 1 mole
= 69.6 g CO₂
Answer: 0.0008636 kilometers
Explanation:
Answer:
C₆H₁₂O₆ < NaCl ≈ CH₃OH < MgCl₂
Step-by-step explanation:
The formula for <em>osmotic pressure</em> (Π) is
Π = icRT
If T is constant,
Π = kic
<em>C₆H₁₂O₆:
</em>
Π = k × 1 × 1 = k
<em>MgCl₂:
</em>
Π = k × 3 × 1 = 3k
<em>CH₃OH:
</em>
Π = k × 1 × 2 = 2k
<em>NaCl:
</em>
Π = k × 2 × 1 = 2k
The order of osmotic pressures is
C₆H₁₂O₆ < NaCl ≈ CH₃OH < MgCl₂
The volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.
<h3>How to calculate volume?</h3>
The volume of a given gas can be calculated using the following Charle's law equation:
V1/T1 = V2/T2
Where;
- T1 = initial temperature
- T2 = final temperature
- V1 = initial volume
- V2 = final volume
- V1 = 9L
- V2 = ?
- T1 = 325K
- T2 = 450K
9/325 = V2/450
325V2 = 4050
V2 = 4050/325
V2 = 12.46L
Therefore, the volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.
Learn more about volume at: brainly.com/question/2817451
The answer is cells
The answer is cells
