What is the solution to this equation? (1/4)x+1 =32 A. -7/2 B. -2 C. 3/2 D. 2

Evaluate the following functions at x = 10 q(x)=x^2-2x+2

Oduvanchick [21]

Answer:

82

Step-by-step explanation:

given:x=10

Evaluating,

(10)²-2(10)+2

=100-20+2

=80+2

=82

Pls mark me brainliest

5 0

3 years ago

If x = 2 calculate the value of x squared- x

monitta

Plug the x value which is 2 back to the x and solve.

I gave you two answers because I wasn’t sure if the question was (x^2) - 2 or x^2-2.
Those two functions look similar but is totally different so keep that in mind.

Hope you have a victorious day!

4 0

3 years ago

Compute and simplify 4 /9 + 13/18 show work

Darya [45]

Answer:

$1\frac{1}{6}$

Step-by-step explanation:

so first find the common denominator which is 162

so on 4/9 multiply 18 to denominater and numerator which makes it 72/162

next multiply 9 to numerator and denominator in 13/18 which makes it 117/162

so now add:

$\frac{72}{162} +\frac{117}{162} = \frac{189}{162}$

so now simplification.

189/162 can be reduced by 3

63/54 is our new answer. now we can reduce it by 9

7/6 is our new answer. now we must change it to a mixed number which is $1\frac{1}{6}$

hope this helped!

6 0

4 years ago

The bad debt ratio for a financial institution is defined to be the dollar values of loans defaulted divided by the total dollar

Nimfa-mama [501]

Answer:

(a) NULL HYPOTHESIS, $H_0$ : $\mu \leq$ 3.5%

ALTERNATE HYPOTHESIS, $H_1$ : $\mu$ > 3.5%

(b) We conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Step-by-step explanation:

We are given that a random sample of seven Ohio banks is selected.The bad debt ratios for these banks are 7, 4, 6, 7, 5, 4, and 9%.The mean bad debt ratio for all federally insured banks is 3.5%.

We have to test the claim of Federal banking officials that the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

(a) Let, NULL HYPOTHESIS, $H_0$ : $\mu \leq$ 3.5% {means that the the mean bad debt ratio for Ohio banks is less than or equal to the mean for all federally insured banks}

ALTERNATE HYPOTHESIS, $H_1$ : $\mu$ > 3.5% {means that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks}

The test statistics that will be used here is One-sample t-test;

T.S. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean debt ratio of Ohio banks = 6%

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 1.83%

n = sample of banks = 7

So, test statistics = $\frac{6-3.5}{\frac{1.83}{\sqrt{7} } }$ ~ $t_6$

= 3.614

(b) Now, at 1% significance level t table gives critical value of 3.143. Since our test statistics is more than the critical value of t so we have sufficient evidence to reject null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Hence, Federal banking officials claim was correct.

7 0

3 years ago

the ratio of the number of adults to the number of students at the prom has to be 1:10. Last year there were 450 more students t

Lisa [10]

Answer:

about 48 adults , because you have to divide the 477 by 10

Step-by-step explanation:

I got this question on my test and i chose this and i got it right.

I hope this helps!! :)

4 0

3 years ago