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stepladder [879]
3 years ago
7

1. A quadratic function of the form 'y ax bx c = ++ has a leading coefficient, a, that is positive and a turning

Mathematics
1 answer:
Zanzabum3 years ago
6 0

Answer: plz report i'm trying to delete my account?!?!

Step-by-step explanation:

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Suppose 8x + 16 ice cream cones
kvv77 [185]

Answer:

B. 152 + 7

Step-by-step explanation:

(8x + 16) + (7x - 9)

8x + 16 + 7x - 9

15x + 16 - 9

15x + 7

None of these options have this answer, so we see A and B:

A. x + 7

B. 152 + 7

It can't be A because we have 15x and A is x + 7

By process of elimination we have B. 152 + 7

x = 10 and 2/15

8 0
3 years ago
When estimating 1,320÷6,why is rounding not a good strategy
Ede4ka [16]
Bc that’s not the right strategy to use it
3 0
3 years ago
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Which of the following statements is false?
Arturiano [62]

Answer:

A

Step-by-step explanation:

Same reason as d

That's the answer.

3 0
3 years ago
If a shape is cut ______ to the base, then the cross section looks just like the base
svetoff [14.1K]

Answer:

Triangle

Step-by-step explanation:

7 0
3 years ago
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from the top of a 120-foot high tower an air traffic controller observes an airplane on the runway at an angle of depression of
Crazy boy [7]
Data:
h (<span>Tower height) = 120 ft
d (</span><span>Distance from the base of the tower to the airplane) = ?
</span>\alpha (<span>Angle formed from observation of the tower to the airplane)=19º

Data: tg 19º </span>≈ 0.34
<span>
Note: </span><span>The angle formed is tangent to the height of the tower and the distance from the base of the tower to the airplane.

</span><span>Formula:
</span>tg \alpha =  \frac{opposite\:leg}{adjacent\:leg}
<span>
Solving:
</span>tg \alpha = \frac{opposite\:leg}{adjacent\:leg}
tg 19^0 = \frac{h}{d}
tg 19^0 = \frac{120}{d}
0.34 =  \frac{120}{d}
0.34*d = 120
0.34d = 120
d =  \frac{120}{0.34}
\boxed{\boed{d \approx 352.9\:ft}}\end{array}}\qquad\quad\checkmark

Answer:
<span>Distance from the base of the tower to the airplane is aproximately  352.9 ft</span>

6 0
3 years ago
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