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elena55 [62]
3 years ago
11

Mary had 60$ and spent 3/4 on a coat. plus she brought a skirt with 1/2 she had left . how much do she have left?

Mathematics
1 answer:
evablogger [386]3 years ago
5 0
3/4 of $60 = $45 for the coat
60 - 45 = $15 left
1/2 of $15 = $7.50 for the skirt
15 - 7.50 = $7.50 left
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|6m−2|=0 please help
Deffense [45]

Answer:

m = 1/3

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Izzie recently took a math test where each correct answer (a) on the main part of the test was worth 8.3 points. She also correc
Temka [501]

Answer:

12 correct answers

Step-by-step explanation:

Since in the main part she scores 8.3 points for each question she answers correctly, we can assume that the number of questions she answers correctly=a

Therefor, the total number of points she achieved in the math test in the main part alone can be expressed as:

Total score(main part)=8.3×a=8.3a points

She also solved a bonus question worth=11 points

Consider expression 1 below

The total score in the whole test=Total score in the main part+Bonus points, where;

Total score in the whole test=110.6 points

Total score in the main part=8.3a points

Bonus points=11 points

Substituting the values in expression 1:

8.3a+11=110.6

8.3a=110.6-11

8.3a/8.3=99.6/8.3

a=12

Number of correct answers in the main part=a=12

4 0
4 years ago
1.) What is the equation of the path of firework #1? Write your equation in general form.
valina [46]

1. I'm assumig that the paths are perfect parabolas

this means that their general forms can be written in y=ax^2+bx+c

it's easier to find vertex form first then expand to get general form

vertex form is y=a(x-h)^2+k where the vertex is (h,k) and a is a constant


firework #1

vertex is (10,50), so (h,k)=(10,50) and h=10, k=50

h_1=a(t-10)^2+50

to find the value of a, subsitute another point

(0,0)

0=a(0-10)^2+50)

0=100a+50

a=\frac{-1}{2}

so the equation in vertex form is h_1=\frac{-1}{2}(t-10)^2+50

expand to get general form

h_1=\frac{-1}{2}(t^2-20t+100)+50

h_1=\frac{-1}{2}t^2+10t-50+50

h_1=\frac{-1}{2}t^2+10t





2.

same as last time

vertex is (10,72) so (h,k)=(10,72) so h=10 and k=72

equation is h_2=a(t-10)^2+72

find a

use another point

(0,22)

22=a(0-10)^2+72

22=100a+72

-50=100a

a=\frac{-1}{2}

so the equation in vertex form is h_2=\frac{-1}{2}(t-10)^2+72




3.

range is the numbers that h is allowed to be

think about what h represents. it represents the height of the rocket

from the graph, we can see that the lowest possible height is 0yd and the highest height is 50yd

so range is 0 to 50 or 0≤h≤50


domain is the numbers that t is allowed to be

think about what t represents. it represents how long the rocket has been flying

it will stop flying when it hits the ground or at t=20

it starts flying at t=0

so domain is from 0 to 20 or 0≤t≤20

3 0
3 years ago
Chips numbered 1 through 80 are shuffled in a basket. One chip is randomly selected.
meriva
1/16

multiples 15,30,45,60, and 75 making 5/80 then you simplify to 1/16
8 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!
scoray [572]

Answer:

AM = 900

CI = 500

I have to be honest, this is the most ridiculously worded question of this type that I have ever seen... ask you teacher, why it was so important to force you to solve it using only one variable?

Step-by-step explanation:

(AM) + (1400-AM) = 1400

2(AM) + 3(1400 - AM) = 3300

2AM + 4200 -3AM = 3300

-AM = -900

AM = 900

CI = 500

4 0
3 years ago
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