Answer:
Answer: RStoic
Explanation:
The reactor i will select to model this reactor in Aspenplus is RStoic
with the following reason;
Reason: Rstoic is used in Aspen software when the stoichiometry of reaction is known but kinetics isn't available. It can have one or more feed streams attached to it.
Reasons why other reactors are not preferred:
RYield: RYield performs the calculations based on the yield and we are not provided with the yield.
REquil: REquil is used when we are provided with stoichiometry of the reaction and information about equilibrium constant so that to perform chemical and phase equilibrium reactions & we are not provided with the equilibrium information.
RGibbs: Since reactor and products are in the gas phase, so it is not required to use it as it's used to minimise Gibbs free energy.
RCSTR: Reaction kinetics needed but we are not provided with it.
RPlug: Reaction kinetics needed but we are not provided with it.
RBatch: Reaction kinetics needed but we are not provided with it.
Answer:
0.14% probability of observing more than 4 errors in the carpet
Explanation:
When we only have the mean, we use the Poisson distribution.
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
The number of weaving errors in a twenty-foot by ten-foot roll of carpet has a mean of 0.8.
This means that
What is the probability of observing more than 4 errors in the carpet
Either we observe 4 or less errors, or we observe more than 4. The sum of the probabilities of these outcomes is 1. So
We want P(X > 4). Then
In which
0.14% probability of observing more than 4 errors in the carpet
Answer:
The circuit impedance is 3.84 phase 38.65º and the voltage across the capacitor is 0.13 phase -128.65º V.
Explanation:
Since the voltage given to us was Vs = 5*cos(5t) V and it is the form of V = Vmax*cos(omega*t) V we can extract the frequency omega, wich is w = 5 rad/s.
In the circuit we have a capacitor and a inductor. The capacitor impedance is negative and it is inversely proportional to the frequency, while the inductor impedance is positive and directly proportional to the frequency. So we have:
Z = R + jw*L - j/(wC)
Z = 3 + j*5*0.5 - j/(5*2)
Z = 3 + j*2.5 - j*0.1 = 3 + j*2.4 Ohm = 3.84 phase 38.65º Ohm
To find out the voltage across the capacitor we can use a voltage divider equation that is:
Vcapacitor = [Zcapacitor/(R + Zinductor + Zcapacitor)] * Vsource
Vcapacitor = [(-j0.1)/(3 + j2.4)]*Vsource
Vcapacitor = [(0.1 phase -90º)/(3.84 phase 38.65º)]*5 phase 0º
Vcapacitor = [0.026 phase -128.65º]* 5 phase 0º
Vcapacitor = 0.13 phase -128.65º V
It may be an engine cooler, or it may be for the boats speed
But I think it is for cooling the engine down