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irakobra [83]
3 years ago
15

Consider flow in between two parallel plates located a distance H from each other. Fluid flow is driven by the bottom plate movi

ng to the right with a velocity of U (note, NO pressure gradient). The top plate has a fixed temperature of TT and the bottom plate has a temperature of Tb. Starting with the governing equations for incompressible flow, find the velocity profile and the temperature profile for the flow in between the plates. In addition, what is an expression for the heat flux at the bottom plate (assuming a thermal conductivity of k)
Engineering
1 answer:
katrin2010 [14]3 years ago
8 0
Wow I don’t
Know but I would
Help you
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Which of these items is least likely to cause an exhaust emission test failure as of a result of excessive nox emissions? a) poo
Iteru [2.4K]

The item that is least likely to cause an exhaust emission test failure as of a result of excessive nox emissions is; poorflow through the egr system.

<h3 /><h3>What is an exhaust emission?</h3>

Exhaust emissions simply means substances emitted into the atmosphere from the exhaust discharge nozzle of an aircraft or aircraft engine.

Now, when the test fails as a result  of excessive nox emissions, we can say that high NOx emissions can occur when an engine's air-fuel mixture is too lean. Thus, we can conclude that the reason for exhaust emission test failure as of a result of excessive nox emissions is due to poorflow through the egr system.

Read more about emissions at; brainly.com/question/14154063

7 0
3 years ago
What is the effect of the workpiece specific cutting energy on the cutting forces, and why?
ella [17]

Explanation:

Specific cutting energy:

   It the ratio of power required to cut the material to metal removal rate of material.If we take the force required to cut the material is F and velocity of cutting tool is V then cutting power will be the product of force and the cutting tool velocity.

Power P = F x V

Lets take the metal removal rate =MRR

Then the specific energy will be

    sp=\dfrac{F\times V}{MRR}

If we consider that metal removal rate and cutting tool velocity is constant then when we increases the cutting force then specific energy will also increase.

8 0
4 years ago
The signal propagation time between two ground stations in a synchronous satellite link is about millisecond is​
Sonja [21]

Answer:

270 is the answer for that

6 0
3 years ago
Find the resultant of the force system on the body OABC as shown .find the points where the resultant will cut the X and Y axis?
MAXImum [283]

Explanation:

the resultant force =

\sqrt{}  {x}^{2}  +  {y}^{2}

5 0
3 years ago
The water in a large lake is to be used to generate electricity by the installation of a hydraulic turbine-generator at a locati
Lynna [10]

Answer:

a) 0.76

b) 0.80

c) 1964 kW

Explanation:

GIVEN DATA:

\dot m = 5000 kg/s

Assume Mechanical energy at exist is negligible

A) Take lake bottom as reference, and then kinetic and potential energy  are taken as zero.

change in mechanical energy is givrn as

e_{in} - e_{out} = \frac{P}{\rho} - 0 = gh = 9.81 \times 50( \frac{1 kJ/kg}{1000 m^2/s^2}

                         = 0.491 kJ/kg

\Delta \dot E_{mec} = \dot m (e_{in} - e_{out}) = 5000 \times 0.491 = 2455 kW

\eta_{OVERALL}  = \frac{\dot W}{\Delta \dot E_{mec}} = \frac{1862}{2455} = 0.76

B) \eta -{gen} = \frac{\eta_{overall}}{\eta_{gen}} = \frac{0.76}{0.95} = 0.80

c) \dot W_{shaft} = \eta_{overall} \left | \Delta \dot E_{mec} \right | = 0.80(2455)

\dot W_{shaft} = 1964 kW

7 0
4 years ago
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