Answer:
a, c
Explanation:
As the problem statement tells you, the phasor technique cannot be used when the frequencies are different. The frequencies are different when the coefficients of t are different. The different ones are highlighted.
a. 45 sin(2500t – 50°) + 20 cos(1500t +20°)
b. 25 cos(50t + 160°) + 15 cos(50t +70°)
c. 100 cos(500t +40°) + 50 sin(500t – 120°) – 120 cos(500t + 60°) -100 sin(10,000t +90°) + 40 sin(10, 100t – 80°) + 80 cos(10,000t)
d. 75 cos(8t+40°) + 75 sin(8t+10°) – 75 cos(8t + 160°)
Answer:
- hoop stress
- longitudinal stress
- material used
all this could led to the failure of the garden hose and the tear along the length
Explanation:
For the flow of water to occur in any equipment, water has to flow from a high pressure to a low pressure. considering the pipe, water is flowing at a constant pressure of 30 psi inside the pipe which is assumed to be higher than the allowable operating pressure of the pipe. but the greatest change in pressure will occur at the end of the hose because at that point the water is trying to leave the hose into the atmosphere, therefore the great change in pressure along the length of the hose closest to the end of the hose will cause a tear there. also the other factors that might lead to the failure of the garden hose includes :
hoop stress ( which acts along the circumference of the pipe):
αh = 
EQUATION 1
and Longitudinal stress ( acting along the length of the pipe )
αl = 
EQUATION 2
where p = water pressure inside the hose
d = diameter of hose, T = thickness of hose
we can as well attribute the failure of the hose to the material used in making the hose .
assume for a thin cylindrical pipe material used to be
≥ 20
insert this value into equation 1
αh = 
= 60/2 = 30 psi
the allowable hoop stress was developed by the material which could have also led to the failure of the garden hose
Answer:
Explained
Explanation:
In the experiment, an (18)O-labelled alcohol R('18)OH is used with normal unlabeled carboxylic acid RC(16)O2H:
The esterification reaction is:
(note: the bracketed values are atomic masses)
RC(16)O_2H + R'(18)OH => RC16O18OR' + H_2(16)O
Since the alcohol is the nucleophile in this nucleophilic substitution reaction, it adds to the carbonyl group of the carboxylic acid and the (18)O atom becomes incorporated into the ester product, while the (16)OH group of the carboxylic acid is expelled as H_2(16)O.
By using mass spectroscopy to measure the mass of the ester and water products, it can be shown that each ester molecule contains one (18)O atom and one (16)O atom, while the water molecules contains only (16)O atoms.
This would prove unequivocally that the ester contains one O atom from the carboxylic acid and one O atom from the alcohol, while the water contains only O atoms from the carboxylic acid.
Explanation:
Step1
Degree of freedom is the number of independent variable which is required to define motion of the system. Degree of freedom is the number of possible motion of the system. Motion can be sliding or rotate. So, there are maximum 6 possible motions of the system, 3 of rotation and 3 of translation. There are 6 maximum possible degrees of freedoms.
Step2
Take an example of slider that is allowed to slide only. So, the slider will have one degree of freedom. Take an example of cylinder which can rotate as well as slide. So, it will have 2 degree of freedom.
