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shepuryov [24]
3 years ago
15

A) Describe the operation of a heat pump operating on the theoretical reversed Carnot cycle, with a neat sketch of the layout.

Engineering
1 answer:
kicyunya [14]3 years ago
3 0

Answer:

a) The operation of a heat pump involves the extraction of energy in the form of heat Q₁ from a cold source

b) The modifications required to convert a plant operating on an ideal Carnot cycle to a plant operating on a Rankine cycle involves

i) Complete condensation of the vapor at the condenser to saturated liquid for pumping to the boiler

ii) Heating of the pumped, pressurized water to the boiler pressure

Explanation:

a) 1 - 2. Wet vapor enters compressor where it undergoes isentropic compression to state 2 by work W₁₂  

2 - 3. The vapor enters the condenser at state 2 where it undergoes isobaric and isothermal condensation to a liquid with the evolution of heat  Q₂

3 - 4. The condensed liquid is expanded isentropically with the work done equal to W₃₋₄

4 - 1. At the state 4, with reduced pressure from the previous expansion, the liquid makes its way to the evaporator where it absorbs heat, Q₁, from the body to be cooled.

b. i) Complete condensation of the vapor at the condenser to saturated liquid for pumping to the boiler

Here the condensation process is modified from partial condensation to complete condensation at the same temperature which reduces the size of the pump required to pump the liquid water as opposed to pumping steam plus liquid

ii) Heating of the pumped, pressurized water to the boiler pressure

The pumped water at state 4 will be required to be heated to saturated water temperature equivalent to the boiler pressure, hence heat will need to be added at state.

Sketches of the schematic of a Basic Rankine cycle is attached  

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Your friend offers to pay you $3,000 five years from now. You'd prefer the money now so you can put it in a bank account at 8% i
zepelin [54]

Answer:

  $958.25

Explanation:

  PV = FV(1 +r)^(-t) . . . . present value of an amount earning rate r compounded annually for t years

  PV = $3000(1.08^-5) ≈ $2041.75

The equivalent present value is $2041.75.

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This amount is less than the offered amount by ...

  $3000 -2041.75 = $958.25

She should pay you $958.25 less in order to make the offers equivalent.

4 0
3 years ago
Which of the following have the capacity to display formatted data?
sukhopar [10]

Answer:

D.  A and B

Explanation:

1. The method Console.Write() is an overloaded method in a language like C#.

One of its variations could be as follows;

<em>Console.Write(String format, Object a, Object b).</em>

This contains three parameters and will write the text representation of the specified objects to the standard output stream using the information specified by the format specifier. Parameter 1 is <em>format</em> which is a composite format string representing the format specifier. Parameter 2 is <em>a</em>, which is the first object to be written using <em>format. </em>Parameter 3 is b, which is the second object to be written using <em>format</em>.

2. The method Console.WriteLine() has the same characteristics as Console.Write() above, except that it writes the text representation of the specified objects, followed by current line terminator then to the standard output stream using the information specified by the format specifier.

3. Console.WriteFormat() does not exist, at least not in C# or .NET

Therefore, Console.Write() and Console.WriteLine() have the capacity to display formatted data.

<em>Hope this helps!</em>

6 0
3 years ago
A Carnot refrigeration cycle absorbs heat at -12 °C and rejects it at 40 °C. a)-Calculate the coefficient of performance of this
tresset_1 [31]

Answer:

a)COP=5.01

b)W_{in}=2.998 KW

c)COP=6.01

d)Q_R=17.99 KW

Explanation:

Given

T_L= -12°C,T_H=40°C

For refrigeration

  We know that Carnot cycle is an ideal cycle that have all reversible process.

So COP of refrigeration is given as follows

COP=\dfrac{T_L}{T_H-T_L}  ,T in Kelvin.

COP=\dfrac{261}{313-261}

a)COP=5.01

Given that refrigeration effect= 15 KW

We know that  COP=\dfrac{RE}{W_{in}}

RE is the refrigeration effect

So

5.01=\dfrac{15}{W_{in}}

b)W_{in}=2.998 KW

For heat pump

So COP of heat pump is given as follows

COP=\dfrac{T_h}{T_H-T_L}  ,T in Kelvin.

COP=\dfrac{313}{313-261}

c)COP=6.01

In heat pump

Heat rejection at high temperature=heat absorb at  low temperature+work in put

Q_R=Q_A+W_{in}

Given that Q_A=15KW

We know that  COP=\dfrac{Q_R}{W_{in}}

COP=\dfrac{Q_R}{Q_R-Q_A}

6.01=\dfrac{Q_R}{Q_R-15}

d)Q_R=17.99 KW

5 0
4 years ago
Pls answer and I will give a like!
lubasha [3.4K]

Answer:

a

Explanation:

6 0
3 years ago
Suzanne Brett wants to borrow $55,000 from the bank. The interest rate is 6.5% and the term is for 5 years.
Otrada [13]

Answer: $14575

$55000

6.5%

5 years

Total Payment Amount: $72875

Yearly payment :$72875/5= $14575

8 0
2 years ago
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