Answer:
a) (option B) 230 kPa
b) (option A) 100 N/m
Explanation:
Given:
Diameter, d = 25 m
Thicknesses, t = 15 mm
Yield point = 240 MPa
Factor of safety = 2.5
a) To find the maximum internal pressure, let's use the formula:
Solving for P, we have:
P = 230.4 kPa
≈ 230 kPa
The maximum permissible internal pressure is nearly 230kPa
b) Given:
Thickness, t = 6.35 mm
L = 203 mm
Torque, T = 8 N m
Let's find the mean Area,
mA = (l - t)²
= (203 - 6.5)²
= 38671.22mm²
≈ 0.03867 m² (converted to meters)
To find the average shear flow, let's use the formula:
q = 103.4 N/m approximately 100N/m
The average shear force flow is most nearly 100 N/m
Answer:
874 psi
Explanation:
Given a sample mean (x') = 900,
and a standard error (SE) = 10
At 99% confidence, Z(critical) = 2.58
That gives 99% confidence interval as,
x' ± Z(critical) x SE = 900 ± 2.58 x 10
The value of the lower limit is,
900 - 25.8 = 874.2
≈ 874 psi
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