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bija089 [108]
3 years ago
14

With an explanation please!

Physics
1 answer:
Setler79 [48]3 years ago
8 0

Answer:

39,000 Joules of Work

Explanation:

Work can be found out through the change in Kinetic Energy.

W = ΔKE

Change in KE is:

W = KE_{Final}  - KE_{Initial}

Expand the equation you get:

W=\frac{1}{2} mv^{2}_{f}  -\frac{1}{2} mv^{2}_{i}

Plugin the known values and solve:

W=\frac{1}{2} (500)(16)^{2}  -\frac{1}{2} (500)(10)^{2}

W=(250)(256)  -(250)(100)

W=64000-25000

W=39000 J

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A current of 0.8 A flows through the motor for 3 minutes. Calculate the total charge in this time.
mixas84 [53]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The given terms are :

Current = 0.8 Amperes

Time = 3 minutes = 3 × 60 = 180 seconds

we know that,

  • current =  \dfrac{charge}{time}

now, let's solve for charge (q) :

  • 0.8 =  \dfrac{q}{180}

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Total Charge (q) = 144 Coulombs

7 0
3 years ago
If the electron just misses the upper plate as it emerges from the field, find the speed of the electron as it emerges from the
Scilla [17]

The speed of the electron as it emerges from the field is; 388.587 m/s

<h3>What is the speed of the electron?</h3>

Initial speed; v₀x = 1.1 * 10⁶ m/s

Acceleration in horizontal direction = 0 m/s²

distance; s_x = 2 cm = 0.02 m

Thus, formula to find time here is;

t = s_x/v₀x

t = 0.02/(1.1 * 10⁶)

t = 1.82 * 10⁻⁶ s

Now for the vertical distance; v,y_o = 0 m/s

Thus, the equation of motion becomes;

s_y = ¹/₂at²

0.005 = ¹/₂a(1.82 * 10⁻⁶)²

Solving for a gives;

a = 3.02 * 10¹³ m/s²

Thus the speed of the electron as it emerges from the field is;

v² = u² + 2as

v = √(0² + 2(3.02 * 10¹³ * 0.005))

v = 388.587 m/s

Read more about Electron speed at; brainly.com/question/15094100

#SPJ1

Complete Question is;

An electron is projected with an initial speed v0 = 1.1 * 10⁶ m/s into the uniform field between the parallel plates. The distance between the plates is 1 cm and the length of the plates is 2 cm. Assume that the field between the plates is uniform and directed vertically downward, and that the field outside the plates is zero. The electron enters the field at a point midway between the plates. E = N/C

find the speed of the electron as it emerges from the field?.

6 0
1 year ago
(1 point) A projectile is fired from ground level with an initial speed of 600 m/sec and an angle of elevation of 30 degrees. Us
konstantin123 [22]

Answer:

(a) The range of the projectile is 31,813.18 m

(b) The maximum height of the projectile is 4,591.84 m

(c) The speed with which the projectile hits the ground is 670.82 m/s.

Explanation:

Given;

initial speed of the projectile, u = 600 m/s

angle of projection, θ = 30⁰

acceleration due to gravity, g = 9.8 m/s²

(a) The range of the projectile in meters;

R = \frac{u^2sin \ 2\theta}{g} \\\\R = \frac{600^2 sin(2\times 30^0)}{9.8} \\\\R = \frac{600^2 sin (60^0)}{9.8} \\\\R = 31,813.18 \ m

(b) The maximum height of the projectile in meters;

H = \frac{u^2 sin^2\theta}{2g} \\\\H = \frac{600^2 (sin \ 30)^2}{2\times 9.8} \\\\H = \frac{600^2 (0.5)^2}{19.6} \\\\H = 4,591.84 \ m

(c) The speed with which the projectile hits the ground is;

v^2 = u^2 + 2gh\\\\v^2 = 600^2 + (2 \times 9.8)(4,591.84)\\\\v^2 = 360,000 + 90,000.064\\\\v = \sqrt{450,000.064} \\\\v = 670.82 \ m/s

5 0
3 years ago
Which is the correct order from the closest to the sun to the farthest away from the sun?
luda_lava [24]

Put your bet down on Choice 'A'.  The others are just flat wrong.


6 0
3 years ago
Average running speed is 8km/h. Convert this to m/s :
rosijanka [135]

Answer:

Im not sure if you mean miles per hour or meters per hour but if it is miles it is 4.97 miles per hour and if it is meters then it is 8000 meters per hour

Explanation:

Sorry if I'm wrong

6 0
3 years ago
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