Technician A says that during a power balance test, the cylinder that causes the biggest RPM drop is the weak cylinder.Technicia
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Answer:
a) If the mass is doubled, then the period is increased by . Hence, the period of the system is 2.828 seconds.
b) If the mass is halved, then the period is reduced by . Hence, the period of the system is 1.414 seconds.
c) The period of the system does not depend on amplitude. Hence, the period of the system is 2 seconds.
d) If the spring constant is doubled, then the period is reduced by . Hence, the period of the system is 1.414 seconds.
Explanation:
The statement is incomplete. We proceed to present the complete statement: <em>A block attached to a spring with unknown spring constant oscillates with a period of 2.00 s. What is the period if </em><em>a. </em><em>The mass is doubled? </em><em>b.</em><em> The mass is halved? </em><em>c.</em><em> The amplitude is doubled? </em><em>d.</em><em> The spring constant is doubled? </em>
We have a block-spring system, whose angular frequency () is defined by the following formula:
(1)
Where:
- Spring constant, measured in newtons per meter.
- Mass, measured in kilograms.
And the period (), measured in seconds, is determined by the following expression:
(2)
By applying (1) in (2), we get the following formula:
a) If the mass is doubled, then the period is increased by . Hence, the period of the system is 2.828 seconds.
b) If the mass is halved, then the period is reduced by . Hence, the period of the system is 1.414 seconds.
c) The period of the system does not depend on amplitude. Hence, the period of the system is 2 seconds.
d) If the spring constant is doubled, then the period is reduced by . Hence, the period of the system is 1.414 seconds.
<u>Answer:</u> The freezing point of solution is -3.34°C
<u>Explanation:</u>
Vant hoff factor for ionic solute is the number of ions that are present in a solution. The equation for the ionization of calcium nitrate follows:
The total number of ions present in the solution are 3.
- To calculate the molality of solution, we use the equation:
Where,
= Given mass of solute
= 11.3 g
= Molar mass of solute
= 164 g/mol
= Mass of solvent (water) = 115 g
Putting values in above equation, we get:
- To calculate the depression in freezing point, we use the equation:
where,
i = Vant hoff factor = 3
= molal freezing point depression constant = 1.86°C/m.g
m = molality of solution = 0.599 m
Putting values in above equation, we get:
Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.
= 3.34 °C
Freezing point of water = 0°C
Freezing point of solution = ?
Putting values in above equation, we get:
Hence, the freezing point of solution is -3.34°C