Answer:
Explanation:
Given that
Mass of bowling ball M1=7.2kg
The radius of bowling ball r1=0.11m
Mass of billiard ball M2=0.38kg
The radius of the Billiard ball r2=0.028m
Gravitational constant
G=6.67×10^-11Nm²/kg²
The magnitude of their distance apart is given as
r=r1+r2
r=0.028+0.11
r=0.138m
Then, gravitational force is given as
F=GM1M2/r²
F=6.67×10^-11×7.2×0.38/0.138²
F=9.58×10^-9N
The force of attraction between the two balls is
F=9.58×10^-9N
One very handy electrical formula is
Power dissipated by a resistance = (Voltage)²/(resistance) .
24 kilowatts = (240 v)² / Resistance
Multiply each side by (Resistance):
(Resistance) x (24 kilowatts) = (240 v)²
Divide each side by (24 kilowatts):
Resistance = (240 v)² / (24,000 watts)
Resistance = (57,600 / 24,000) (volt² / volt · Amp)
Resistance = 2.4 (volt/Amp)
Resistance = 2.4 Ohms
The law of physics that this scenario would violate is the law of conservation of energy.
<h3>What is the law of conservation of energy?</h3>
The law of conservation of energy states that energy possessed by an object or physical body can neither be created nor destroyed but can only be transformed from one form to another.
This ultimately implies that, the energy possessed by the rock at the beginning must be equal to the energy possessed by the rock at the end in accordance with the law of conservation of energy.
Read more on energy here: brainly.com/question/1242059
Answer:
Explanation:
Because of the following ,it is useful to select both objects as the system during collision between an electron and a hydrogen atom
1. The total momentum of the system does not change during the collision.
2.The forces the objects exert on each other are internal to the system and don't change the total momentum of the system.
3. During the time interval just before to just after the collision, external forces are negligible.
Answer:
|v| = 8.7 cm/s
Explanation:
given:
mass m = 4 kg
spring constant k = 1 N/cm = 100 N/m
at time t = 0:
amplitude A = 0.02m
unknown: velocity v at position y = 0.01 m
1. Finding Ф from the initial conditions:
2. Finding time t at position y = 1 cm:
3. Find velocity v at time t from equation 2:
