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Verizon [17]
4 years ago
11

It took 1.5 hours for a bus to go from one city to the next the bus traveled at an average velocity of 52 mph, west how far apar

t were the two cities
Physics
1 answer:
melisa1 [442]4 years ago
5 0

Answer:

78 miles

Explanation:

The average velocity of the bus is given by:

v=\frac{d}{t}

where

d is the displacement (the distance between the two cities)

t is the time taken

In this problem, we have

t = 1.5 h

v = 52 mph

So, we can solve the formula to find d, the distance between the cities:

d=vt=(52 mph)(1.5 h)=78 mi

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3. Which part of the back seat of a car—the left side, the right side, or the
Nina [5.8K]

Answer:

The sides

Explanation:

Because there's a seat in front of the child to avoid him/her from flying

7 0
4 years ago
How much work is done when a 25-N horizontal force is applied to a 10-kg box, causing it to move 5 meters?
Katarina [22]

Answer:

W=50*sin(25)

Explanation:

W=F*D*sin(25)

W=10*5*sin(25)

W=50*sin(25)

8 0
3 years ago
An electron is accelerated from rest by a potential difference of 412 V. It then enters a uniform magnetic field of magnitude 18
Salsk061 [2.6K]

Explanation:

Given that,

Potential difference, V = 412 V

Magnitude of magnetic field, B = 188 mT

(a) The potential energy of electron is balanced by its kinetic energy as :

eV=\dfrac{1}{2}mv^2

v is speed of the electron

v=\sqrt{\dfrac{2eV}{m}} \\\\v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\times 412}{9.1\times 10^{-31}}} \\\\v=1.2\times 10^7\ m/s

(b) When the charged particle moves in magnetic field, it will move in circular path. The radius of the circular path is given by :

r=\dfrac{mv}{eB}\\\\r=\dfrac{9.1\times 10^{-31}\times 1.2\times 10^7}{1.6\times 10^{-19}\times 188\times 10^{-3}}\\\\r=3.63\times 10^{-4}\ m

Hence, this is the required solution.                                

7 0
3 years ago
( I will give a brainliest )
True [87]

Answer:

The answer is temperature lol

Explanation:

:)

4 0
3 years ago
81. a baseball is hit straight up and is caught by the catcher 2.0 s later, at the same height at which it left the bat. the max
andrew-mc [135]

The maximum height of the ball during this interval is 4.9 m (Option A)

<h3>How to determine the time to reach maximum height</h3>

The time taken to reach the maximum height can be obtained as follow:

  • Time for the entire trip (T) = 2 s
  • Time to reach maximum height (t) = ?

T = 2t

2 = 2t

Divide both side by 2

t = 2 / 2

t = 1 s

<h3>How to determine the maximum height reached by the ball</h3>

The maximum height reached by the ball can be obtained as follow:

  • Acceleration due to gravity (g) = 9.8 m/s²
  • Time to reach maximum height (t) =?
  • Maximum height (h) =?

h = ½gt²

h = ½ × 9.8 × 1²

h = ½ × 9.8 × 1

h = 4.9 m

Thus, the maximum height reached by the ball is 4.9 m (Option A)

Learn more about motion under gravity:

brainly.com/question/22719691

#SPJ1

7 0
1 year ago
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