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Margaret [11]
3 years ago
14

Please help me with this

Mathematics
2 answers:
mixer [17]3 years ago
7 0
C. rose bush $3, shrub $2
pogonyaev3 years ago
4 0
Hghguvccgviggvhvdhvh
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Will mark brainlest help me please​
Allushta [10]

Answer:

  • no le entiendo por qué estás en inglés

7 0
3 years ago
Jace's average gross pay is $1,630.00 bi-weekly. Determine how many years it will take Jace to earn his first million dollars.
vesna_86 [32]

The number of years it will take to earn his first million is 24 years

Average bi-weekly gross pay = $1,630

Bi-weekly = 2 weeks

Number of 2 weeks(bi-weeks) in a year = 26 bi-weeks

The least million he can earn is $1,000,000

Let the number of years = n

We could use the equation :

Least million = gross pay × (Number of bi-weeks × number of years)

1000000 = 1630 × (26n)

1000000 = 42380

Divide both sides by 34230

1000000 / 42380 = n

n = 23.59

The least number of years is 24.

Learn more : brainly.com/question/18796573

6 0
3 years ago
Chandler, Jamal, Allison, and Qi are given the following problem. In 1982, Wayne Gretsky set a record for the greatest number of
Pavel [41]

Answer:

The correct answer is B.

Step-by-step explanation:

Since Chandler, Jamal, Allison, and Qi are given the following problem: "In 1982, Wayne Gretsky set a record for the greatest number of hockey goals in one season with 92 goals. If a player has scored 60 goals this season and averages 2 goals per game, how many additional games must he play to break the record? ", And each student writes an inequality to represent the situation:

Chandler wrote 60 + 2g ≥ 92

Jamal wrote 60 + 2g> 92

Allison wrote 60 + 2g <92

Qi wrote 60 + 2g ≤ 92

To determine whose inequality is correct, the following calculation must be performed:

92 - 60 = 32

32/2 = 16

Chandler: 60 + 2x16 ≥ 92

Thus, Chandler wrote the correct option.

6 0
3 years ago
A product comes in cans labeled "38 oz". A random sample of 10 cans had the following weights:
KiRa [710]

Answer:

b. 35.9, 39.1 ounces

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

barX=37.465 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=2.27 represent the sample standard deviation

n=10 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

barX +- t*[(s)/(sqrt{n))]   (1)

In order to calculate the critical value t we need to find first the degrees of freedom, given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that t_(alpha/2)=2.26

Now we have everything in order to replace into formula (1):

37.465-2.26[(2.27)/(sqrt{10))]=35.9    

37.465+2.26[(2.27)/(sqrt{10))]=39.1

So on this case the 95% confidence interval would be given by (35.9;39.1)    

7 0
4 years ago
Determine the asymptotes of the function: y=x^3-5x^2+4x-25/x^2-4x+3
igomit [66]

Answer:

Vertical A @ x=3 and x=1

Horizontal A nowhere since degree on top is higher than degree on bottom

Slant A @ y=x-1  

Step-by-step explanation:

I'm going to look for vertical first:

I'm going to factor the bottom first:  (x-3)(x-1)

So we have possible vertical asymptotes at x=3 and at x=1

To check I'm going to see if (x-3) is a factor of the top by plugging in 3 and seeing if I receive 0 (If I receive 0 then x=3 gives me a hole)

3^3-5(3)^2+4(3)-25=-31 so it isn't a factor of the top so you have a vertical asymptote at x=3

Let's check x=1

1^3-5(1)^2+4(1)-25=-25 so we have a vertical asymptote at x=1 also

There is no horizontal asymptote because degree of top is bigger than degree of bottom

There is a slant asympote because the degree of top is one more than degree of bottom (We can find this by doing long division)

                       x   -1

                --------------------------------------------------

x^2-4x+3 |      x^3-5x^2+4x-25

                  - ( x^3-4x^2+3x)

                   --------------------------------

                            -x^2 +x  -25

                       -   (-x^2+4x-3)

                          ---------------------

                                   -3x-22

So the slant asymptote is to x-1

8 0
3 years ago
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