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ss7ja [257]
2 years ago
9

HELP MEEEEEE PLEASE<3

Mathematics
2 answers:
Mama L [17]2 years ago
4 0

Answer:

3 3/5 miles

Step-by-step explanation:

6 3/4 divided by 1 7/8=

3 3/5

MrRa [10]2 years ago
4 0
3 3/5 is the answer
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4 students equally share 2/3 of a pizza
oee [108]

\frac{2}{3} *4

=\frac{2*4}{3}

=\frac{8}{3}

2.67 or 2 \frac{2}{3}

6 0
3 years ago
Please help!! 15 points!!
vampirchik [111]

- 1 =  - 3 - 4 \cos(4θ +  \frac{2\pi}{3} )  \\  - 1 + 4 \cos(4θ +  \frac{2\pi}{3} )  =  - 3 \\ 4 \cos(4θ +  \frac{2\pi}{3} )  =  - 3 + 1 \\ 4 \cos(4θ  + \frac{2\pi}{3} )  =  - 2 \\  \cos(4θ  + \frac{2\pi}{3} )  =  -  \frac{1}{2}  \\  \cos(4θ +  \frac{2\pi}{3} )  =  -  \frac{1}{2}  \\  \cos(2\pi - (4θ +  \frac{2\pi}{3} ))  =  -  \frac{1}{2}  \\ 4θ +  \frac{2\pi}{3}  = arccos( -  \frac{1}{2} ) \\  \cos( \frac{4\pi}{3}  - 4θ)  =  -  \frac{1}{2}

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3 years ago
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PLEASE I NEED AN ANSWER ASAP! THANK YOU.
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D....the empty weight is 160gr
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Please help. Thank you
MariettaO [177]

Answer:

$105

Step-by-step explanation:

6 0
2 years ago
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angel's dad bought a television for her completing all of her digital learning day lesson. he want to warp the gift. the box mea
atroni [7]

Answer: 13 sheets of paper

Step-by-step explanation:

We are given the dimensions of the box and the wrap paper:

Box:

(56 in)(8 in)(36 in)

Warp paper:

(26 in)(17 in)

Now we need to find the surface area of the box and the area of the wrap paper:

Box:

surface_{1}=(56 in)(8 in)(2)=896 in^{2}

surface_{2}=(8 in)(36 in)(2)=576 in^{2}

surface_{3}=(56 in)(36 in)(2)=4032 in^{2}

surface-area=896 in^{2}+576 in^{2}+4032 in^{2}=5504 in^{2}

Warp paper:

area=(26 in)(17 in)=442 in^{2}

Dividing the area of the box by the area of the paper:

\frac{surface-area}{area}=\frac{5504 in^{2}}{442 in^{2}}=12.45 \approx 13

This means Angel's dad needs to purchase 13 sheets of wrapping paper.

4 0
3 years ago
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