Your limting the amount of sandbags you have if you take away and when your adding your adding more sandbags.
Answer:
a.Z(-2,1)
b.Z(1,1)
c.Z(-3,2)
Step-by-step explanation:
z(-2,3)
Imagine this point on a graph.
Translate it down two units :
the x stays -2, by going down the y decreases 2 so 3-2=1
Z(-2,1)
Translate Right three units : I'm assuming that we use the answer from the first translation
Z(-2,1)
The y doesn't change this time the x increases 3 since we're moving to the right.
Z(1,1)
Translate up 1 and left 4:
Z(1,1)
by moving up one we have Z(1,2) then by moving 4 to the left we get Z(-3,2)
Hope this helps :)
Answer:
A.) gf(x) = 3x^2 + 12x + 9
B.) g'(x) = 2
Step-by-step explanation:
A.) The two given functions are:
f(x) = (x + 2)^2 and g(x) = 3(x - 1)
Open the bracket of the two functions
f(x) = (x + 2)^2
f(x) = x^2 + 2x + 2x + 4
f(x) = x^2 + 4x + 4
and
g(x) = 3(x - 1)
g(x) = 3x - 3
To find gf(x), substitute f(x) for x in g(x)
gf(x) = 3( x^2 + 4x + 4 ) - 3
gf(x) = 3x^2 + 12x + 12 - 3
gf(x) = 3x^2 + 12x + 9
Where
a = 3, b = 12, c = 9
B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)
To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula
Y = 3x + 3
X = 3y + 3
Make y the subject of formula
3y = x - 3
Y = x/3 - 3/3
Y = x/3 - 1
Therefore, g'(x) = x/3 - 1
For g'(12), substitute 12 for x in g' (x)
g'(x) = 12/4 - 1
g'(x) = 3 - 1
g'(x) = 2.
Answer:6x2=12-10=2 and 4×+3=12
Step-by-step explanation:
