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Fudgin [204]
3 years ago
13

Brett rented ice skates for 34 hour. The total cost was $5.25. What is the cost per hour of renting the ice skates?

Mathematics
2 answers:
bonufazy [111]3 years ago
6 0

Answer:

$0.15 per hour

Step-by-step explanation:

$5.25÷34=0.15441176

Round that to the nearest cent. Which would equal $0.15.

Umnica [9.8K]3 years ago
5 0
0.15 per hour

I DONT IF THIS IS CORRECT OR NOT.
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Hey, Its the same person. This is Algebra 2. Please Help!
suter [353]

Answer:

first option

Step-by-step explanation:

Given

f(x) = \frac{2x^2+5x-12}{x+4} ← factorise the numerator

     = \frac{(x + 4)(2x-3)}{x+4} ← cancel (x + 4) on numerator/ denominator

     = 2x - 3

Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is

x = - 4

Substitute x = - 4 into the simplified f(x) for y- coordinate

f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11

The discontinuity occurs at (- 4, - 11 )

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2x - 3 = 0 ⇒ 2x = 3 ⇒ x = \frac{3}{2}

There is a zero at ( \frac{3}{2}, 0 )

Thus

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7 0
3 years ago
What is 800 divided by 90
solong [7]
8.8 (repeating decimal)
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The quantities x and y are proportional. Find the constant of proportionality r in the equation y = rx
ELEN [110]

Answer:

r = 7

Step-by-step explanation:

To solve this, we can plug in a pair of x and y values and solve for r.

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1. The probability of telesales representative making a sale on a customer call is 0.15.
Mumz [18]

Answer:

1c

 n = 33

1d

 n = 19

Step-by-step explanation:

From the question we are told that

   The  probability of telesales representative making a sale on a customer call is  p = 0.15

     The mean is  \mu  =  5

Generally the distribution of sales call  made by a  telesales representative follows a binomial distribution  

i.e  

         X  \~ \ \ \  B(n , p)

and the probability distribution function for binomial  distribution is  

      P(X = x) =  ^{n}C_x *  p^x *  (1- p)^{n-x}

Here C stands for combination hence we are going to be making use of the combination function in our calculators  

Generally the mean is mathematically represented as

     \mu =  n*  p

=>  5= n *  0.15

=>  n = 33

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      P( X \ge 1) = 1 - P( X < 1 ) > 0.95

=>    P( X \ge 1) = 1 - P( X =0 ) > 0.95

=>    P( X \ge 1) = 1 - [ ^{n}C_0 *  (0.15 )^0 *  (1- 0.15)^{n-0}] > 0.95

=>    1 - [1  *  1*  (0.85)^{n}] > 0.95

=>    [(0.85)^{n}] > 0.05

taking natural  log of both sides

n = \frac{ln(0.05)}{ln(0.85)}

=>  n = 19

3 0
2 years ago
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