Answer:
jvjjvscsjcsjsvjscjsvhchhcuhcjwcwh ejcisvsufjdtsydghcwhcjwvhsvjscekfdjsvjsfjsvkdvs
Step-by-step explanation:
30y
the answer is false
.....................................
You would divide 121 by 8.
121 / 8 = 15.125 So she did about 15 sit ups in a minute. Hope this helps!
If the box is a square and the length of one side is 46cm, then the area of the box in square centimeters is 46 * 46 = 2116.
Final Answer:
d. 2116
Hope I helped :)


- <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>

- <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>


According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.
<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>





<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>
The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse
