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Reika [66]
2 years ago
11

If the scale is 2inches = 5miles. What is the amount of miles in 4 inches?

Mathematics
1 answer:
LUCKY_DIMON [66]2 years ago
6 0

Answer:

D. 10 miles

Step-by-step explanation:

As you know 2 inches=5miles so if you add 2 more inches that is equal to 5 miles you will have to add 5 and 5 which equal 10 miles.

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2xy , cu x + y = 9 divizibil cu 2. repede va roggg
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Step-by-step explanation:

30y

7 0
3 years ago
{8} ⊆ {7,8,9} true or false
Natalija [7]

the answer is false

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6 0
3 years ago
Read 2 more answers
Abby did 121 sit ups in 8 minutes estimate the number of sit ups she did in 1 minute
const2013 [10]
You would divide 121 by 8.
121 / 8 =  15.125 So she did about 15 sit ups in a minute. Hope this helps!
 
4 0
3 years ago
Read 2 more answers
Emily put toys into a square box that is 46 centimeters long. How many square centimeters is the bottom of the box?
Sedaia [141]
If the box is a square and the length of one side is 46cm, then the area of the box in square centimeters is 46 * 46 = 2116.
Final Answer:
d. 2116
Hope I helped :)
7 0
3 years ago
A triangle with sides 11m , 13m and 18m is a right triangle.<br> ​<br> A<br> True<br> B<br> False
Julli [10]

\bold{\huge{\pink{\underline{ Solution}}}}

\bold{\underline{ Given :-}}

  • <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>

\bold{\underline{ To \: Find :-}}

  • <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>

\bold{\underline{ Let's \: Begin :-}}

\sf{\red{ In \:right \:angled\ : triangle, }}

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>

\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}

\sf{(AB)² + (BC)² = (AC)²}

\sf{ (11)² + (13)² = (18)² }

\sf{ 121 + 169 ≠  324 }

\sf{ 290 ≠ 324  }

<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>

The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse

\sf{\blue{ Hence,\: Your\: answer \:is \:false }}

5 0
2 years ago
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