Answer:
Let the Dulcina's collection be 'x'
Let the Tremaine collection be 'x-39'
x + x - 39 =129
2x = 129 +39
2x = 168
x = 168/2
x = 84
Dulcina's collection = x = 84
Tremaine's collection = x - 39 = 84 - 39 = 45
Answer: m²-9mn+2n²
Step-by-step explanation: make use of BODMAS strategy. Let the unknown be x.
-7mn+2m²+3n²-x= m²+2mn+n². Since we are concerned about getting the unknown,let's try to collect the like terms.
-7mn+2m²+3n²-(m²+2mn+n²)= x
-7mn+2m²+3n²-m²-2mn-n²= x
-7mn-2mn+2m²-m²+3n²-n²=x
-9mn+m²+2mn= x
X= m²-9mn+2n²
You make them to improper fractions then you find a greatest common factor and then go from there
2 < x < 5
i think this is the answer
First we must find the volume of the cube. This is equal to side^3. 4^3=64 cubic inches. Since the pebbles are .5 pounds per cubic inch and we assume it is packed we multiply the volume by .5
This will give 32 pounds
