Before the driver applies the brakes ( with the reaction time ):
d 1 = v0 · t = 20 m/s · 0.53 s = 10.6 m
After that:
v = v0 - a · t1
0 = 20 m/s - 7 · t1
7 · t1 = 20
t1 = 2.86 s
d 2 = v 0 · t1 - a · t1² / 2
d 2 = 20 m/s · 2.86 s - 7 m/s² · (2.86 s)²/2 = 57.2 m - 28.6 m = 28.6 m
d = d 1 + d 2 = 10.6 m + 28.6 m = 39.2 m
Answer: the stopping distance of a car is 39.2 m.
Answer:
5
Step-by-step explanation:
Here LCM will be 6. (We made the denominator same)
so, now the equation will be :
= 5/6
So, the value in the red box is 5.
Hope it helps!
First you must change 3/8 into a decimal, so the number would be 45.375. To find scientific notation you have to move the decimal between a factor of 1-10. 4.5375 . You moved over the decimal once toward the left. so scientific notation would be 4.5375 X 10^1
The distance covered by the motorcycle is 31.4 km and displacement will be equal to 0.
<h3>
What is Distance and Displacement ?</h3>
Distance and Displacement both are the measure of the movement of an Object from one point to another.
Distance is a scalar quantity while Displacement is a vector quantity , and so it depends upon direction.
Distance travelled will always be positive but Displacement can be positive , negative and zero.
A motorcycle rides from point P to Q to R to S and finally to P in a circular path as shown in the below figure
The missing figure is attached with the answer.
(a) The distance covered by the motorcycle is
2πr = 2 * 3.14 * 5 = 31.4 km
(b) The displacement will be equal to 0 as the starting and the ending point is same.
To know more about Distance and Displacement
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Umm im gonna guess on this one because im not good at math lol
, 3.58?