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Cerrena [4.2K]
3 years ago
8

what is the second longest wavelength for a standing wave on a wire with one fixed end and one open end that is 3.0 m long?

Physics
1 answer:
olga2289 [7]3 years ago
4 0
Is there any multiple choice answers? Any options?
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If the seafloor is spreading why isn't earth getting bigger?
tatyana61 [14]
Well there are areas of the seafloor that are spreading due to tectonic plates moving apart but there are also places where these plates meet and one slides under the other (subduction zones) as a result, the earth is not getting bigger since these two actions cancel each other out.<span>
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7 0
3 years ago
The human eye can readily detect wavelengths from about 400 nm to 700 nm. part a if white light illuminates a diffraction gratin
Lera25 [3.4K]

We are given that the wavelength ʎ is from 400 nm to 700 nm. The formula for this is:

d sin a =m * ʎ

where,

d = slit separation = 1 mm / 750 lines = 1/750

a = angle

m = 1

ʎ = 400 nm to 700 nm = 0.0004 mm to 0.0007 mm

 

Rewriting the formula in terms of angle a:

a = sin^-1 (m ʎ / d)

 

when ʎ = 0.0004 mm

a = sin^-1 (0.0004 / (1/750))

a = 17.46°

 

when ʎ = 0.0007 mm

a = sin^-1 (0.0007 / (1/750))

a = 31.67°

 

Hence the range of angles is from 17.46° to 31.67<span>°.</span>

3 0
3 years ago
An object has an acceleration of 12.0 m/s/s. If the mass of this object were tripled (with no change in its net force), then its
yaroslaw [1]

Answer:

If it is triple it means we multiply it by 3 then it is 36.3 m/s/s

8 0
3 years ago
Your mass is 65 kg. you stand on a bathroom scale in an elevator on earth. (a) what force would the scale exert when the elevato
erik [133]
I think you would use F = ma
F = 65*10
F = 650N
(The 10m/s is from acceleration due to gravity)
4 0
3 years ago
A 85 kg lineman tackles a 90 kg receiver. The receiver is running 5.8 m/s, and the lineman is moving 4.1 m/s, at a right angle t
weeeeeb [17]

Answer:

3.59 m/s

Explanation:

We are given that

Mass of lineman,m=85 kg

Mass of receiver,m'=90 kg

Speed of receiver,v'=5.8 m/s

Speed of lineman,v=4.1 m/s

\theta=90^{\circ}

We have to find the their velocity immediately after the tackle.

Initial momentum,P_i=\sqrt{p^2_1+p^2_2}=\sqrt{(85\times 4.1)^2+(90\times 5.8)^2}=627.6 kgm/s

According to law of conservation of momentum

Initial momentum=Final momentum=(m+m')V

627.6=(85+90)V=175V

V=\frac{627.6}{175}=3.59 m/s

3 0
3 years ago
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