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charle [14.2K]
3 years ago
7

A student pushes a 50-N box across the floor a distance of 15 m. How much work was done to move the box?

Physics
2 answers:
andrezito [222]3 years ago
7 0

Answer:

750 j

Explanation:

I took the test in k12

irinina [24]3 years ago
4 0

Answer:750

Explanation:

50 times 15

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During normal beating, a heart creates a maximum 3.95-mV potential across 0.305 m of a person’s chest, creating a 0.75-Hz electr
WINSTONCH [101]

Answer:

E = 0.0130 V/m.

Explanation:

The electric field is related to the potential difference as follows:

E = \frac{\Delta V}{d}

<u>Where:</u>

E: is electric field

ΔV: is the potential difference = 3.95 mV  

d: is the distance of a person's chest = 0.305 m

Then, the electric field is:

E = \frac{\Delta V}{d} = \frac{3.95 \cdot 10^{-3} V}{0.305 m} = 0.0130 V/m

Therefore, the maximum electric field created is 0.0130 V/m.

I hope it helps you!

7 0
3 years ago
How often must you check the temperature of food that is being held with temperature control?.
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You need to check the temperature of food being stored in a temperature-controlled environment every four hours. The process of changing a space's temperature is called temperature control.

Cooking food alone may not be enough to avoid food poisoning, though, if the bacteria in food are allowed to grow to large numbers. When the temperature is between 5°C and 63°C, bacteria can grow. The risk zone is the range between 5°C and 63°C.

Temperature control is a process where the passage of heat energy into or out of a space or substance is adjusted to achieve the desired temperature. This process involves measuring or otherwise detecting changes in the temperature of the space (and all of the objects contained therein) or of the substance.

Learn more about temperature here

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6 0
1 year ago
A CFL bulb has an efficiency of 8.9% and a power of 22 W. How much light energy does the lightbulb produce in 1 second
hjlf
The power that the light is able to utilize out of the supply is only 0.089 of the given.
                           Power utilized = (0.089)(22 W)
                                                  = 1.958 W
                                                  = 1.958 J/s
The energy required in this item is the product of the power utilized and the time. That is,
                           Energy = (1.958 J/s)(1 s) = 1.958 J
Thus, the light energy that the bulb is able to produce is approximately 1.958 J. 
6 0
3 years ago
Read 2 more answers
6. question is in the picture
Harlamova29_29 [7]
The answer is c you got to look for answers that make sense
8 0
3 years ago
Capacitances of 10uF and 20uF are connected in parallel,
jarptica [38.1K]

Answer:

The equivalent capacitance will be 15\mu F  

Explanation:

We have given two capacitance C_=10\mu F\ and\ C_2=20\mu F

They are connected in parallel

So equivalent capacitance C=C_1+C_2=10+20=30\mu F

This equivalent capacitance is now connected in series with 30\mu F

In series combination of capacitors the equivalent capacitance is given by \frac{1}{C}=\frac{1}{30}+\frac{1}{30}

C=\frac{30}{2}=15\mu F

So the equivalent capacitance will be 15\mu F  

5 0
3 years ago
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