False, There are situations where 5.00$ off would be better than 20% off.
Answer:
-0.5 or -1/2 or A
Step-by-step explanation:
180 degrees is Pi radians. To find out what the measure is in the paranthesees, divide 180 by 6 and get 30. Now multiply it by 7 to get 210. The question is asking for the sin(210). The sin of 210 is -0.5
The 1st Quartile that the Box-and-Whisker Plot shows tells us that: <em>A. Three fourths of the fish he caught were larger than 22 pounds.</em>
Recall:
- In a Box-and-Whisker Plot, about 25% of the data will be below the first quartile while 75% will be above the first quartile, that is Three fourths of the data will be above the first quartile and one-fourths will be below the first quartile.
Thus, the given Box-and-Whisker Plot as shown in the diagram below shows that the first quartile is 22 pounds.
Therefore, the 1st Quartile that the Box-and-Whisker Plot shows tells us that: <em>A. Three fourths of the fish he caught were larger than 22 pounds.</em>
Learn more about Box-and-Whisker Plot on:
brainly.com/question/12343132
We have to identify the quadrilateral with no line of symmetry and have rotational symmetry.
Line of symmetry is the imaginary line which divide the given quadrilateral in two equal halves.
Rotational symmetry is when an object is rotated around a center point (turned) a number of degrees and the object appear the same.
Parallelogram is a quadrilateral which has no line of symmetry as we can not draw any imaginary line which divides the parallelogram in two equal halves.
But Parallelogram has rotational symmetry as when a parallelogram is rotated around a center point (turned) a number of degrees and parallelogram appear the same.
Hence, Parallelogram is the quadrilateral.
Answer:
(x +4)(x -1)(x +1)
Step-by-step explanation:
The sum of coefficients is zero, so we know that x=1 is a root and x-1 is a factor. We also notice that pairs of terms have coefficients in the ratio 1:4, so x+4 will also be a factor.
= (x+4)(x^2) -1(x+4)
= (x+4)(x^2 -1)
= (x +4)(x -1)(x +1) . . . . . use the factoring of the difference of squares
