Answer:
We conclude that segment QR is the shortest.
Hence, option B is true.
Step-by-step explanation:
First, we need to determine the missing angle m∠R
Given the triangle Δ∠PQR
m∠P = 48°
m∠Q = 83°
m∠R = ?
We know the sum of angles of a triangle is 180°.
m∠P+m∠Q+m∠R = 180°
48°+83°+m∠R=180°
m∠R = 180° - 48° - 83°
m∠R = 49°
Thus, the value of m∠R = 49°
We know that the longest side in a triangle is opposite the largest angle, and the shortest side is opposite the smallest angle.
Here,
m∠P = 48° is the shortest angle.
As the side QR segment is opposite the smallest angle i.e. m∠P = 48°
Therefore, we conclude that segment QR is the shortest.
Hence, option B is true.
First you must know that for remarkable angles: cos (0) = 1, cos (π) = - 1, cos (π / 2) = 0, cos (3π / 2) = 0, cos (2π) = 1. Then, by simple substitution in the given formula, you can find the solutions of x. Which for the interval [0, 2π) are: x = π, x = pi divided by two and x = three pi divided by two.Attached solution.
Slot method or permutations
top 3
6 for first slot
5 for 2nd slot
4 for 3rd
6*5*4=120
120 possiblites
answer is C
Answer: 4 ÷ 0.96 = 4.16666666667
Step-by-step explanation:
Replace x = 3 into <span>6/x + 2x^2
</span>6/x + 2x^2
=6/3 + 2 (3)^2
= 2 + 2(9)
= 2 + 18
= 20
