Ask question

Ask question

All categories

3 years ago

12

Pls help me I don’t know this!!!

2 answers:

Mamont248 [21]3 years ago

4 0

Angle G is 144 degrees because it makes a linear pair with angle 36

liubo4ka [24]3 years ago

3 0

Answer:

The angle value is 112°.

Step-by-step explanation:

I attached a pic with all the angles that help you find it. Rely on opposite vertex angles and supplementary angles on parallel lines to find the answer.

You might be interested in

Please hurry up .......

andre [41]

Answer:

I think the answer is D.

4 0

2 years ago

Read 2 more answers

The cost of renting the party room at a restaurant is $50.00. Snacks cost $13.50 per person. Write an expression to describe the

alexandr1967 [171]

Answer:an expression to describe the total cost of a party is written as

y = 13.50p + 50

Step-by-step explanation:

The cost of renting the party room at a restaurant is $50.00. Snacks cost $13.50 per person. Assuming the total number of persons invited for the party is p, and the total cost of renting the party room is y. Therefore an expression to describe the total cost of a party is written as

y = 13.50p + 50

The $50 always remains constant

3 0

3 years ago

Help, please I can't answer it

Ivan

Answer:

A and c i think it will help you

5 0

3 years ago

Consider the formula for the slope between two coordinate points, m, shown below. Which of the following equations is equivalent

o-na [289]

Answer:

Answer is A

Step-by-step explanation:

$m = y2 - y1 \div x2 - x1 \\ y2 = m(x2 - x1) + y1$

6 0

4 years ago

x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco

igomit [66]

Answer:

$x=-cos(t)+2sin(t)$

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

$a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0$

Will have a characteristic equation of the form:

$a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0$

Where solutions $r_1,r_2...,r_n$ are the roots from which the general solution can be found.

For real roots the solution is given by:

$y(t)=c_1e^{r_1t} +c_2e^{r_2t}$

For real repeated roots the solution is given by:

$y(t)=c_1e^{rt} +c_2te^{rt}$

For complex roots the solution is given by:

$y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)$

Where:

$r_1_,_2=\lambda \pm \mu i$

Let's find the solution for $x''+x=0$ using the previous information:

The characteristic equation is:

$r^{2} +1=0$

So, the roots are given by:

$r_1_,_2=0\pm \sqrt{-1} =\pm i$

Therefore, the solution is:

$x(t)=c_1cos(t)+c_2sin(t)$

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of $x(t)$ in order to find the constants $c_1$ and $c_2$ :

$x'(t)=-c_1sin(t)+c_2cos(t)$

Evaluating the initial conditions:

$x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1$

And

$x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2$

Now we have found the value of the constants, the solution of the second-order IVP is:

$x=-cos(t)+2sin(t)$

3 0

3 years ago