Periodicity in chemical properties is based on atomic structure." explain.

Chemistry

1 answer:

Alja [10]3 years ago

3 0

Answer:

Periodicity is caused by regular and predictable variations in element atomic structure. ... The rows in the periodic table (the periods) reflect the filling of electrons shells around the nucleus, so when a new row begins, the elements stack on top of each other with similar please help me rank up

You might be interested in

Density = Mass = 14 g Volume = 2 mL what is the answer to density

Troyanec [42]

Answer:

7ml/g

Explanation:

density=mass/volume

density=14g/2ml

density= 7g/ml

4 0

3 years ago

A box has a length of 10 cm a width of 8.5 cm and a height of 5.5 cm what is it volume?

OleMash [197]

467.5 centimeters. are you sure that's high school chemistry though, lad?

7 0

3 years ago

Read 2 more answers

How many total oxygen (O) atoms are present in the products side of the equation C2H5OH + 3O2 → 2CO2 + 3H2O?

kifflom [539]

Answer:

There are seven oxygen atoms in total on the product side.

Explanation:

The oxygen atom is present in both the species of CO₂ and H₂O. As there are two molecules of CO₂, so the number of oxygen atoms from it will be 4. There are three molecules of H₂O in the product side so oxygen atoms from it will be three. So, the total number of oxygen from both species is seven.

3 0

4 years ago

Upon combustion, a compound containing only carbon and hydrogen produces 2.67 g<img src="https://tex.z-dn.net/?f=CO_%7B2%7D" id=

Hoochie [10]

Answer:

$\boxed{\text{CH$_{2}$}}$

Explanation:

1. Calculate the mass of each element

$\text{Mass of C} = \text{2.67 g } \text{CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{0.7286 g C}\\\\\text{Mass of H} = \text{1.10 g }\text{H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g } \text{{H$_{2}$O}}} = \text{0.1231 g H}$

2. Calculate the moles of each element

$\text{Moles of C = 0.7286 g C}\times\dfrac{\text{1 mol C}}{\text{12.01 g C }} = \text{0.060 67 mol C}\\\\\text{Moles of H = 0.1231 g H} \times \dfrac{\text{1 mol H}}{\text{1.008 g H}} = \text{0.1221 mol H}$