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zheka24 [161]
3 years ago
15

Calculate the amount of CO2 (in kg) released when 1 kg of coal is burned. Assume that carbon content of the coal is 50% by mass.

Chemistry
1 answer:
Delvig [45]3 years ago
4 0

Answer:

1.8321 kg

Explanation:

The given 1 kg of coal contains 50% of the carbon atom by mass. Thus, mass of carbon in coal is \frac {50}{100}\times 1\ kg=0.5\ kg

Also, 1 kg = 1000 g

So, mass of carbon = 500 g

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Molar mass of carbon = 12.0107 g/mol

Moles of methanol = 500 g / 12.0107 g/mol = 41.6295 moles

Considering the reaction:

C+O_2\rightarrow CO_2

From the reaction,

1 mole of C react to form 1 mole of CO_2

So,

41.6295 moles of C react to form 41.6295 moles of CO_2

Moles of CO_2 = 41.6295 moles

Molar mass of CO_2 = 44.01 g/mol

So, Mass = Moles × Molar mass = 41.6295 moles × 44.01 g/mol = 1832.1143 g

Also, 1g = 0.001 kg

<u>So, amount of CO_2 released = 1.8321 kg</u>

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Answer:

\large \boxed{\text{17.mL}}

Explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

p_{1}V_{1} = p_{2}V_{2}

Data:

\begin{array}{rcrrcl}p_{1}& =& \text{123.5 kPa}\qquad & V_{1} &= & \text{25 L} \\p_{2}& =& \text{179.9 kPa}\qquad & V_{2} &= & ?\\\end{array}

Calculations:  

\begin{array}{rcl}123.5 \times 25 & =& 179.9V_{2}\\3088 & = & 179.9V_{2}\\V_{2} & = &\dfrac{3088}{179.9}\\\\& = &\textbf{17 L}\\\end{array}\\\text{The new volume of the gas is } \large \boxed{\textbf{17 L}}

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3 years ago
In which type of chemical reaction are electrons transferred?
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The correct answer is 2. 

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3 years ago
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Before a bond breaks in a chemical reaction, what happens
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By how much will the water temperature increases if 1046 J of heat energy are added. The specific heat of water is 4.184 J/g • °
Brilliant_brown [7]

Answer:

Option A

250 degrees Celcius

Explanation:

If 1046J of heat energy is added to water, the water will experience a rise in temperature, at a rate that is directly proportional to its specific heat capacity.

Mathematically, this can be seen as Q=C\Delta T

Where C = specific heat of water = 4.184 J/g • °C.

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Determine the change in volume that takes place when a 2.00 L sample of N2 gas is heated from 250 C to 500 C.
Effectus [21]

Answer:

V₂ = 2.96 L

Explanation:

Given data:

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Solution:

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According to Charles's law,

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V₂ = T₂V₁/T₁

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V₂ = 2.96 L

4 0
3 years ago
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