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zheka24 [161]
3 years ago
15

Calculate the amount of CO2 (in kg) released when 1 kg of coal is burned. Assume that carbon content of the coal is 50% by mass.

Chemistry
1 answer:
Delvig [45]3 years ago
4 0

Answer:

1.8321 kg

Explanation:

The given 1 kg of coal contains 50% of the carbon atom by mass. Thus, mass of carbon in coal is \frac {50}{100}\times 1\ kg=0.5\ kg

Also, 1 kg = 1000 g

So, mass of carbon = 500 g

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Molar mass of carbon = 12.0107 g/mol

Moles of methanol = 500 g / 12.0107 g/mol = 41.6295 moles

Considering the reaction:

C+O_2\rightarrow CO_2

From the reaction,

1 mole of C react to form 1 mole of CO_2

So,

41.6295 moles of C react to form 41.6295 moles of CO_2

Moles of CO_2 = 41.6295 moles

Molar mass of CO_2 = 44.01 g/mol

So, Mass = Moles × Molar mass = 41.6295 moles × 44.01 g/mol = 1832.1143 g

Also, 1g = 0.001 kg

<u>So, amount of CO_2 released = 1.8321 kg</u>

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A 3.31-g sample of lead nitrate, Pb(NO3)2, molar mass = 331 g/mol, is heated in an evacuated cylinder with a volume of 2.53 L. T
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The latent heat of melting is 80 calories for 1 gram of ice. if 1 gram of ice absorbs 60 calories what do i get?
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Here the latent energy of melting for 1 g of ice is 80 calories and that 1 g of ice only absorbed 60 calories. hence the phase is not changed because it requires more 20 calories to melt.

Hence 1 g of ice remains as its solid phase (ice). 
3 0
3 years ago
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