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satela [25.4K]
2 years ago
10

2(5 - 8x) -13 = 9(1 - x) -12 ​

Mathematics
2 answers:
Ugo [173]2 years ago
8 0

2 (5 - 8x) - 13 = 9 (1 - x) - 12

10 - 16x - 13 = 9 - 9x - 12

10 - 13 - 16x = 9 - 12 - 9x

- 3 - 16x = - 3 - 9x

- 3 + 3 = - 9x + 16x

0 = 7x

0/7 = x

0 = x

_____

Hope it helps ⚜

jenyasd209 [6]2 years ago
8 0

<em><u>Answer:</u></em>

  • x = 0

<em><u>Step-by-step explanation:</u></em>

  • 2(5 - 8x) - 13 = 9(1 - x) -12 ​
  • => 10 - 16x - 13 = 9 - 9x - 12
  • => -3 - 16x = -3 - 9x
  • => 0 = 16x - 9x
  • => 0 = 7x
  • => x = 0

<em><u>Conclusion: </u></em>

Therefore, the answer is 'x = 0'

<em>!! Hoped this helped !!</em>

BrainiacUser1357

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Answer:

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Let's split the figure:

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3 years ago
Match the cofactors to their corresponding entries in the matrix.
Masja [62]

Answer:

The co-factors and their values are shown in the table below.

Step-by-step explanation:

We are given the matrix, \begin{bmatrix}3&7&1\\7&1&-3\\8&5&1\end{bmatrix}.

It is required to match the co-factors with the corresponding values.

As, the co-factors are given by,

A_{c_{ij}} = (-1)^{i+j}(d), where the d= determinant of the matrix after removing the i- row and j- column.

So, we have,

1. A_{c_{11}}.

So, A_{c_{11}}=(-1)^{1+1}(1\times 1-5\times (-3))

i.e. A_{c_{11}}=(-1)^{2}(1+15)=16

2. A_{c_{13}}.

So, A_{c_{13}}=(-1)^{1+3}(7\times 5-1\times 8)

i.e. A_{c_{13}}=(-1)^{4}(35-8)=27

3. A_{c_{21}}.

So, A_{c_{21}}=(-1)^{2+1}(7\times 1-5\times 1)

i.e. A_{c_{21}}=(-1)^{3}(7-5)=-2

4. A_{c_{22}}.

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i.e. A_{c_{22}}=(-1)^{4}(3-8)=-5

5. A_{c_{31}}.

So, A_{c_{31}}=(-1)^{3+1}(7\times (-3)-1\times 1)

i.e. A_{c_{31}}=(-1)^{4}(-21-1)=-22

Thus, we get,

Co-factor                 Value

A_{c_{11}}                              16

A_{c_{13}}                             27

A_{c_{21}}                             -2

A_{c_{22}}                            -5

A_{c_{31}}                           -22

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2 years ago
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arsen [322]

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3 years ago
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