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mina [271]
3 years ago
10

A 10.0-kg crate slides along a raised horizontal frictionless surface at a constant speed of 4.0 m/s. The crate then slides down

a frictionless incline and across a second, roughened horizontal surface as shown in the figure. What is the kinetic energy of the crate as it reaches the lower surface?
Physics
1 answer:
Elodia [21]3 years ago
7 0

The kinetic energy of the crate as it reaches the lower surface is 80 J

Kinetic energy is the energy possed by an object in motion. Mathematically, the kinetic energy can be expressed as follow:

KE = ½mv²

With the above formula, the kinetic energy of the crate can be obtained as follow:

  • Mass (m) = 10 Kg
  • Velocity (v) = 4 m/s
  • Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 10 × 4²

KE = 5 × 16

KE = 80 J

Therefore, the kinetic energy of the crate is 80 J

Learn more about kinetic energy: brainly.com/question/14449170

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We will use Newton’s laws of motion, so

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t=\sqrt{10/49} = 0.45 seconds

<h3>What are the three laws of motion given by Newton?</h3>

The 3 laws of motion given by Newton are as follows:

1) Unless an unbalanced force acts upon it, an item at rest remains at rest, and an object in motion continues to move in a straight line at a constant pace.

2) An object's acceleration is influenced by its mass and the force being applied.

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8 0
4 years ago
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xxTIMURxx [149]

Answer:

the answer is

Explanation:For equilibrium

Weight = Tension

mg=T

∴T=4×3.1π=12.4πN (as can be inferred from the question)

Y=

△l/l

T/A

​

=

1000

0.031

​

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12.4π/π(

1000

2

​

)

2

​

=

4×0.031

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Source: http://wtamu.edu/~cbaird/sq/2013/06/27/have-astronomers-ever-observed-a-violet-shift-like-they-have-blue-shifts-and-red-shifts/

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