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levacccp [35]
3 years ago
6

when a stationary rugby ball is kicked, it is contact with a player's about for 0.05 s. during this short time, the ball acceler

ates at 600m/s/s.calculate the speed at which the ball leaves the player's boot​
Physics
1 answer:
Ad libitum [116K]3 years ago
3 0

Answer:

30 m/s

Explanation:

Applying,

v = u+at................ Equation 1

Where v = final speed of the ball, u = initial speed of the ball, a = acceleration, t = time.

From the question,

Given: u = 0 m/s (stationary), a = 600 m/s², t = 0.05 s

Substitute these values into equation 5

v = 0+(600×0.05)

v = 30 m/s

Hence the speed at which the ball leaves the player's boot is 30 m/s

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Answer:

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A satellite of mass 1000kg is in a circular orbit around a planet. The centripetal acceleration of the satellite in its orbit is
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8 0
3 years ago
Step 2: Apply NEwton's second law Apply ∑Fy = may , what should ay be equal to, since the block doesn't move in the y direction
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Answer:

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8 0
3 years ago
Read 2 more answers
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